Find the unknown sides and angles of this triangle using the Law of Cosines.
1 answer:
Answer:
side c-10.35 Angle a-50.88 Angle B-94.12
Step-by-step explanation:
I found the answers on a khan academy thing. I just took the quiz and got a 100%
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Someone deleted my answer but if you need to look back its 90000
Answer:
5 + 2x = 6
2x = 6-5
2x = 1
x = 0.5
n -3n = 14 -4n
-2n = 14-4n (since 4n is negative, change the sign to make it positive and then add 4n to both sides of the equation)
2n = 14
n = 7
7 (5a - 4) - 1 = 14 - 8a
35a - 28 - 1 = 14 -8a
35a -29 = 14 - 8a
43a = 43
a = 1
Answer:
56
Step-by-step explanation:
6+7b-3a
Substitute:
6+7(8)-3(2)
Solve:
6+56-6
Simplify:
6+50
=56
You just change the mixed number into an improper fraction.
4 3/5
5x4=20
20+3=23
23/5
Alright give me a second ok
