Answer:
36u
Step-by-step explanation:
With like terms, just add normally
Find the surface area of the sphere shown below.
1 answer:
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Answer:
The Translation is 5 units to the right and 8 units up
Step-by-step explanation:
* Lets talk about some transformation
- If the function f(x) translated horizontally to the right
by h units, then the new function g(x) = f(x - h)
- If the function f(x) translated horizontally to the left
by h units, then the new function g(x) = f(x + h)
- If the function f(x) translated vertically up
by k units, then the new function g(x) = f(x) + k
- If the function f(x) translated vertically down
by k units, then the new function g(x) = f(x) – k
* Now lets solve the problem
∵ The parent function is y = (0.5)^x
∵ f(x) = (0.5)^x - 5 + 8 after translation
- The x in the first function is (x - 5) in the second function
∴ There is a horizontal translation to the right 5 units
- the first function is (0.5)^x in the second function y = (0.5)^x - 5 + 8
∴ There is a vertical translation up 8 units
* The Translation is 5 units to the right and 8 units up
- Look to the attached graph to more understand
- The purple graph is y = (0.5)^x
- The black graph is f(x) = (0.5)^x-5 + 8
- To check the answer take a point from the y = (0.5)^x as (0 , 1), the
image of this point on f(x) is (5 , 9)
-The point (0 , 1) is shifted 5 units to the right and 8 units up
∴ Its x- coordinate move from 0 to 5, y- coordinate move from 1 to 9
Answer:
<em>The options are not visible enough (See Explanation)</em>
Step-by-step explanation:
Given
x:- 1 || 2 || 3 || 4 || 5
y:- 13 || 22 || 37 || 58 || 85
Required
Determine if the function is quadratic
Calculate the difference between the values of y
<em>The resulting difference are: 9 || 15 || 21 || 27</em>
Next; Calculate the difference between the difference of values of y
<em>The resulting difference are: 6 || 6 || 6</em>
<em>For the function to be quadratic, the above difference must be the same and since they are the same (6), then the function represents a quadratic function.</em>