The equation has no solution
Answer:
Step-by-step explanation:
Hello, please consider the following.
When the parabola equation is like
The vertex is the point (h,k) and the focus is the point (h, k+1/(4a))
As the vertex is (3,-2) we can say that h = 3 and k = -2.
We need to find a.
The focus is (3,2) so we can say.
So an equation for the parabola is.
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Answer:
49/81
Step-by-step explanation:
[cos(a) + sin(a)]^2 = (1/3)^2
(cos(a))^2 + 2sin(a)cos(a) + (sin(a))^2 = 1/9
(sin(a))^2 + (cos(a))^2 = 1
1 + 2sin(a)cos(a) = 1/9
2sin(a)cos(a) = -8/9
sin(a)cos(a) = -4/9
[cos(a) + sin(a)]^4 = (1/3)^4 = 1/81
(cos(a))^4 + 4sin(a)×(cos(a))^3 + 6×(sin(a))^2×(cos(a))^2 + 4(sin(a))^3×cos(a) + (sin(a))^4 = 1/81
(cos(a))^4 + (sin(a))^4 + 4sin(a)cos(a)((cos(a))^2 + (sin(a))^2) + 6(sin(a)cos(a))^2 = 1/81
cos(a))^4 + (sin(a))^4 + 4sin(a)cos(a)(1) + 6(sin(a)cos(a))^2 = 1/81
(cos(a))^4 + (sin(a))^4 + 4(-4/9) +6((-4/9)^2) = 1/81
(cos(a))^4 + (sin(a))^4 - 16/9 + 6(16/81) = 1/81
(cos(a))^4 + (sin(a))^4 = 1/81 + 16/9 - 6(16/81)
(cos(a))^4 + (sin(a))^4 = 49/81
The tangent of that angle is 4/3.
Sketch a picture of the unit circle for yourself, and plot that point on it. Draw the angle in on the circle, and you'll see that those coordinates are the sides opposite and adjacent to the angle, so their ratio is its tangent.
