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3 years ago

Whats the area of this figure

Mathematics

2 answers:

shusha [124]3 years ago

5 0

The answer to your problem is 341 km

Lady bird [3.3K]3 years ago

4 0

Answer:

341km2

Step-by-step explanation:

7km*25km=175km2

8km*(11km+6km)=136km2

5km*6km=30km2

175km2+136km2+30km2=341km2

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Evaluate the expression. 4–4÷2

n200080 [17]

Answer:

Step-by-step explanation:

7 0

4 years ago

Will give brainliest

dmitriy555 [2]

Answer:

Step-by-step explanation:

Given, 

Radius of the cylinder = 3cm

Height of the cylinder = 3cm

Therefore, 

Lateral surface area of the cylinder

$= 2\pi rh$

$= 2\pi \times 3 \times 3 {cm}^{2}$

$= 2\pi \times 9 {cm}^{2}$

$= 18\pi {cm}^{2}$

Hence,

The required value in the green box will be 18 (Ans)

4 0

3 years ago

Read 2 more answers

Item 7

Mariulka [41]

Answer:

$A = 74.7^\circ$

$B = 42.5^\circ$

$C = 62.8^\circ$

Step-by-step explanation:

Given

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

Required

The measure of each angle

First, we calculate the length of the three sides of the triangle.

This is calculated using distance formula

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

For AB

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$d = \sqrt{(-1 - 2)^2 + (2 - 8)^2$

$d = \sqrt{(-3)^2 + (-6)^2$

$d = \sqrt{45$

So:

$AB = \sqrt{45$

For BC

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

$BC = \sqrt{(2 - 4)^2 + (8 - 1)^2$

$BC = \sqrt{(-2)^2 + (7)^2$

$BC = \sqrt{53$

For AC

$A = (-1,2) \to (x_1,y_1)$

$C = (4,1) \to (x_3,y_3)$

$AC = \sqrt{(-1 - 4)^2 + (2 - 1)^2$

$AC = \sqrt{(-5)^2 + (1)^2$

$AC = \sqrt{26$

So, we have:

$AB = \sqrt{45$

$BC = \sqrt{53$

$AC = \sqrt{26$

By representation

$AB \to c$

$BC \to a$

$AC \to b$

So, we have:

$a = \sqrt{53$

$b = \sqrt{26$

$c = \sqrt{45$

By cosine laws, the angles are calculated using:

$a^2 = b^2 + c^2 -2bc \cos A$

$b^2 = a^2 + c^2 -2ac \cos B$

$c^2 = a^2 + b^2 -2ab\ cos C$

$a^2 = b^2 + c^2 -2bc \cos A$

$(\sqrt{53})^2 = (\sqrt{26})^2 +(\sqrt{45})^2 - 2 * (\sqrt{26}) +(\sqrt{45}) * \cos A$

$53 = 26 +45 - 2 * 34.21 * \cos A$

$53 = 26 +45 - 68.42 * \cos A$

Collect like terms

$53 - 26 -45 = - 68.42 * \cos A$

$-18 = - 68.42 * \cos A$

Solve for $\cos A$

$\cos A =\frac{-18}{-68.42}$

$\cos A =0.2631$

Take arc cos of both sides

$A =\cos^{-1}(0.2631)$

$A = 74.7^\circ$

$b^2 = a^2 + c^2 -2ac \cos B$

$(\sqrt{26})^2 = (\sqrt{53})^2 +(\sqrt{45})^2 - 2 * (\sqrt{53}) +(\sqrt{45}) * \cos B$

$26 = 53 +45 -97.67 * \cos B$

Collect like terms

$26 - 53 -45= -97.67 * \cos B$

$-72= -97.67 * \cos B$

Solve for $\cos B$

$\cos B = \frac{-72}{-97.67}$

$\cos B = 0.7372$

Take arc cos of both sides

$B = \cos^{-1}(0.7372)$

$B = 42.5^\circ$

For the third angle, we use:

$A + B + C = 180$ --- angles in a triangle

Make C the subject

$C = 180 - A -B$

$C = 180 - 74.7 -42.5$

$C = 62.8^\circ$

8 0

3 years ago

John Doe estimates that the price elasticity of demand for new SUVs to be 0.75. If the price of SUVs rose by 15%; would the quan

Charra [1.4K]

If the coefficient of demand for the SUV is 0.75 this means that it has a relatively inelastic demand since it is less than. In other words, there is only a little alteration in demand when prices change.
So when the price of SUV rise by 15%, and it has a coefficient of 0.75, we can anticipate only 11.25% decrease in its demand. This is for the reason that the SUVs do not have many substitutes for it.
So to solve:
(x/15%) = 0.75
Then simply solve for x:
x = (0.75)(0.15) = 11.25%

4 0

3 years ago

If possible, draw a line of symmetry in each of the following figures or words. If it is not possible to draw a line of symmetry

Marrrta [24]

Answer:

a) none

b) vertical through the middle

c) horizontal through the middle

d) none

Step-by-step explanation:

a) A repeated asymmetrical pattern rarely has a line of symmetry. (I can't think of a case where it does.)

b) This figure has left-right symmetry about its centerline. (In general, a light bulb will not, because the screw threads are asymmetrical.)

c) Each of the letters is symmetrical about its horizontal centerline, so the word is as well.

d) The letter S is symmetrical about its center point, but not about any horizontal or vertical line. This word is not symmetrical about any line.

8 0

4 years ago

Whats the area of this figure​

Whats the area of this figure