<span>__Ernest Rutherford__</span>
To get the ratio of the concentration of sodium acetate to the concentration of acetic acid we are going to use H-H equation:
when:
PH = Pka + ㏒[salt/acid]
when the Ka of acetic acid = 1.75 x 10^-5
so, we can get Pka from this formula:
Pka = -㏒Ka
= -㏒1.75 x 10^-5
= 4.76
and when we have PH = 5.75, so by substitution:
∴ 5.75 = 4.76 + ㏒[acetate/ acetic acid]
∴ [acetate/acetic acid] = 9.77
∴ the ratio of a concentration of acetate to acetic acid 9.77
Oxygen and glucose that’s all I know
The volume of O₂ produced: 84.6 L
<h3>Further explanation</h3>
Given
7.93 mol of dinitrogen pentoxide
T = 48 + 273 = 321 K
P = 125 kPa = 1,23365 atm
Required
Volume of O₂
Solution
Decomposition reaction of dinitrogen pentoxide
2N₂O₅(g)→4NO₂(g)+O₂ (g)
From the equation, mol ratio N₂O₅ : O₂ = 2 : 1, so mol O₂ :
= 0.5 x mol N₂O₅
= 0.5 x 7.93
= 3.965 moles
The volume of O₂ :
