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Sliva [168]
3 years ago
7

The coefficient is a number that placed

Chemistry
1 answer:
rjkz [21]3 years ago
8 0

Answer:

in front of the elements

Explanation:

The coefficient tells you how much of each element there is in a molecule.

Hope that helps.

You might be interested in
How many grams of product are formed from 2.0 mol of N2 (g) and 8.0 mol of Mg(s)? Show all calculations leading to an answer. Li
Vaselesa [24]

Balanced chemical reaction happening here is:

3Mg(s) + N₂(g) → Mg₃N₂(s)        


 <u>moles of product formed from each reactant:</u>


2.0 mol of N2 (g) x <u> 1 mol Mg₃N₂      </u>  = <u>2 mol Mg₃N₂</u>

                                    1 mol N2

and


8.0 mol of Mg(s) x <u> 1 mol Mg₃N₂      </u>   = 2.67 mol Mg₃N₂

                                 3 mol Mg


Since N2 is giving the least amount of product(Mg₃N₂) ie. 2 mol Mg₃N₂

N2 is the limiting reactant here and Mg is excess reactant.


Hence mole of product formed here is 2 mol Mg₃N₂    


molar mass of Mg₃N₂    

= 3 Mg + 2 N

= 101g/mol  


mass of product(Mg₃N₂) formed  

= moles x Molar mass

= 2 x 101

= 202g Mg₃N₂


<u>202g of product are formed from 2.0 mol of N2(g) and 8.0 mol of Mg(s).</u>


<u>   </u>   The following are indicators of chemical changes:

Change in Temperature    

Change in Color

Formation of a Precipitate



8 0
3 years ago
Question: How will soap or alcohol affect the hydrogen bonds between different water molecules? Hypothesis: Materials: Penny, wa
Stella [2.4K]

Answer:

A soap or alcohol will interfere with the hydrogen bonding between water molecules making it weaker

Explanation:

A water molecule is polar as the oxygen atom is strongly electronegative and draws the electrons it shares with the hydrogen atoms in the water molecule to itself. This creates a partial negative charge on the oxygen atom and partial positive charges on the hydrogen atoms. The attraction of neighboring oxygen to hydrogen atoms in a water molecule results in hydrogen bonding.

However, a detergent molecule which has a polar head and a hydrophobic tail, when added to water significantly interferes with the hydrogen bonding between water molecules. The polar head is attracted to water molecules whereas the hydrophobic tail of each molecule are not. The detergent molecules form clusters known as micelles with the polar heads attracted to water and the hydrophobic tails directed towards the center of the micelle, away from water molecules. This weakens the hydrogen bonding between water molecules

An alcohol contains a polar -OH group in its molecules. However, the hydrogen bonding between alcohol molecules are weaker than that in water because the other end of the alcohol molecule has a C-O bond which is less polar than the O-H bond. Therefore, when an alcohol is added to water, it weakens the hydrogen bonding in water.

This weakening of the hydrogen bonding in water also has the effect of lowering the surface tension of water.

7 0
3 years ago
Read 2 more answers
Which idea behind the shape of molecules includes the concept that electrostatic repulsion between electron pairs surrounding an
Vladimir79 [104]

Answer:

VSEPR theory

Explanation:

The valence shell electron pair repulsion theory was propounded by Gillespie and Nylom (1957).

The entire idea of the VSEPR theory is that the shape of a molecule depends on the electrostatic repulsion between electron pairs surrounding the central atom in a molecule which causes these pairs to be separated as far as possible.

The shapes of many molecules can be accurately predicted based on this model.

8 0
3 years ago
The reaction 2HI → H2 + I2 is second order in [HI] and second order overall. The rate constant of the reaction at 700°C is 1.57
In-s [12.5K]

Answer:

1.135 M.

Explanation:

  • For the reaction: <em>2HI → H₂ + I₂,</em>

The reaction is a second order reaction of HI,so the rate law of the reaction is: Rate = k[HI]².

  • To solve this problem, we can use the integral law of second-order reactions:

<em>1/[A] = kt + 1/[A₀],</em>

where, k is the reate constant of the reaction (k = 1.57 x 10⁻⁵ M⁻¹s⁻¹),

t is the time of the reaction (t = 8 hours x 60 x 60 = 28800 s),

[A₀] is the initial concentration of HI ([A₀] = ?? M).

[A] is the remaining concentration of HI after hours ([A₀] = 0.75 M).

∵ 1/[A] = kt + 1/[A₀],

∴ 1/[A₀] = 1/[A] - kt

∴ 1/[A₀] = [1/(0.75 M)] - (1.57 x 10⁻⁵ M⁻¹s⁻¹)(28800 s) = 1.333 M⁻¹ - 0.4522 M⁻¹ = 0.8808 M⁻¹.

∴ [A₀] = 1/(0.0.8808 M⁻¹) = 1.135 M.

<em>So, the concentration of HI 8 hours earlier = 1.135 M.</em>

8 0
3 years ago
Why is plant able to continue to grow and develop once starch supply in the seed is gone?
horsena [70]
<span>They have chloroplasts and use light energy to make more food. I think might be wrong </span>
3 0
4 years ago
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