Answer:
Both are 55
Step-by-step explanation:
To solve this problem, set the equations equal to each other, solve for n, then plug in the values
Solve for n:
1. 2n+15=3n-5
2. Add 5 to both sides
3. Now you have 2n+20=3n
4. Subtract 2n from both sides
5. You are left with n=20
Next, plug it in:
1. Replace all n's with 20
2. 2(20)+15=55
3. 3(20)-5=55
There you go! Hope this helps!
Answer:

General Formulas and Concepts:
<u>Algebra I</u>
- Functions
- Function Notation
<u>Calculus</u>
Derivatives
Derivative Notation
Derivative Rule [Chain Rule]: ![\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%20%3Df%27%28g%28x%29%29%20%5Ccdot%20g%27%28x%29)
Derivative: ![\displaystyle \frac{d}{dx} [e^u]=e^u \cdot u'](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Be%5Eu%5D%3De%5Eu%20%5Ccdot%20u%27)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<em />
<em />
<em />
<u>Step 2: Differentiate</u>
- eˣ Derivative [Derivative Rule - Chain Rule]:
![\displaystyle J'(x) = \frac{d}{dx}[e^{f(x)}] \cdot \frac{d}{dx}[f(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20J%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Be%5E%7Bf%28x%29%7D%5D%20%5Ccdot%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28x%29%5D)
- Simplify:

<u>Step 3: Evaluate</u>
- Substitute in <em>x</em> [Derivative]:

- Substitute in function values:

- Simplify:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Derivatives
Book: College Calculus 10e
Yes, the function would be negative
The first equation is 
(Equation 1)
The second equation is
(Equation 2)
Putting the value of x from equation 1 in equation 2.
we get,


by simplifying the given equation,


Using discriminant formula,


Now the formula for solution 'x' of quadratic equation is given by:


Hence, these are the required solutions.
You just need to plug in 1, 2, 3, and 4.
10*4(1)-1=39
10*4(2)-1=79
10*4(3)-1=119
10*4(4)-1=159