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PtichkaEL [24]
3 years ago
13

I don't get why people use this app for non educational purposes and put things that don't even have to do with learning or scho

ol or what brainly was used for. if you don't have an educational question or if you want to say something innapropriate keep it on another app. Thank you
​
Mathematics
2 answers:
Sonbull [250]3 years ago
4 0

Answer:

Like this very "question"? Yes, this question is quite educational and asking for academic help HMMMMM. Ok but yea i see that too much I agree.

Step-by-step explanation:

creativ13 [48]3 years ago
3 0
Preachhhhhhhh preachhhh
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Describe the value of the 9 in 926,415.
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900,000 because that is where the value of 9 is placed in the number.
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Using the following image, determine if the triangles are similar. If so, how?
dolphi86 [110]
They are similar and the answer is SSS
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3 years ago
Mary earns $25 per hour at her job. Next month, she will receive a 10% raise. Complete the two expressions that represent how mu
Natali5045456 [20]
25 + _0.10__*25

25 + __2.5___

In the 1st blank, the answer is 0.1 or 0.10 because you have to change percents to decimals to find the raise. 10% as a decimal = 0.1 or 0.10

In the 2nd blank, the answer is 2.5 because on the top, it's 0.1*25, which equals 2.5, and 2.5 is the raise. All you have to do is multiply 10%, or 0.1, by 25, and you get 2.5.

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6 0
4 years ago
Austin keeps a right conical basin for the birds in his garden as represented in the diagram. The basin is 40centimeters deeps a
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n indepe
-Dominant- [34]

Answer: 0.0031

Step-by-step explanation:

Binomial distribution formula :-

P(x)=^nC_xp^x(1-p)^{n-x}, where P(x) is the probability of x successes in the n independent trials of the experiment and p is the probability of success.

Given : A binomial probability experiment is conducted with the given parameters.

n=9,\ p=0.8,\ x\leq3

Now, P(x\leq3)=P(3)+P(2)+P(1)+P(0)

=^9C_3(0.8)^3(1-0.8)^{9-3}+^9C_2(0.8)^2(1-0.8)^{9-2}+^9C_1(0.8)^1(1-0.8)^{9-1}+^9C_0(0.8)^0(1-0.8)^9\\\\=\dfrac{9!}{3!6!}(0.8)^3(0.2)^6+\dfrac{9!}{2!7!}(0.8)^2(0.2)^7+\dfrac{9!}{1!8!}(0.8)(0.2)^8+\dfrac{9!}{0!9!}(0.2)^9=0.003066368\approx0.0031

Hence,  P(x\leq3)=0.0031

8 0
4 years ago
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