The students in math class use square tiles to make arrays. If they
- use 8 (8=1·2·2·2) tiles, then they can form arrays of the length in 1 tile, 2 tiles, 4 tiles and 8 tiles;
- use 9 (9=1·3·3) tiles, they can form arrays of the length in 1 tile, 3 tiles and 9 tiles (one array less).
So, you can conclude that Celia is correct.
Im not sure what your asking
Answer:
45
Step-by-step explanation:
9, 13, 17, 21, 25
We are adding 4 each time
9+4 = 13
13+4 =17
17+4 = 21
The common difference =4
a1 = 9
The formula is
an = a1+d(n-1) where n is the term number
an = 9+4(n-1)
We want the 10th term
a10 = 9+4(10-1)
= 9+4(9)
= 9+36
= 45
The unknown number is 1/2 or 0.5.
ex: 4x+6=8
Answer:6
Step-by-step explanation:
-4xy
-4(1/2)(-3)
-4(-1.5)
6