A bag of cookies can be shared equally among 2,,3,4,5, or 6 friends. What is the least number of cookies the bag could have?
1 answer:
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Answer:
x = 4.45 or x = - 4.45
Step-by-step explanation:
Here are the steps:
Substitute the values,
÷ 2 × 1
x = 2 ± √6
x = 4.45 or x = - 4.45
<em>good luck, i hope this helps :)</em>
We can set it up like this, where <em>s </em>is the speed of the canoeist:
To make a common denominator between the fractions, we can multiply the whole equation by s(s-5):
![s(s-5)[\frac{18}{s} + \frac{4}{s-5} = 3] \\ 18(s-5)+4s=3s(s-5) \\ 18s - 90+4s=3 s^{2} -15s](https://tex.z-dn.net/?f=s%28s-5%29%5B%5Cfrac%7B18%7D%7Bs%7D%20%2B%20%5Cfrac%7B4%7D%7Bs-5%7D%20%3D%203%5D%20%5C%5C%2018%28s-5%29%2B4s%3D3s%28s-5%29%20%5C%5C%2018s%20-%2090%2B4s%3D3%20s%5E%7B2%7D%20-15s)
If we rearrange this, we can turn it into a quadratic equation and factor:
Technically, either of these solutions would work when plugged into the original equation, but I would use the second solution because it's a little "neater." We have the speed for the first part of the trip (9 mph); now we just need to subtract 5mph to get the speed for the second part of the trip.
The canoeist's speed on the first part of the trip was 9mph, and their speed on the second part was 4mph.
To make a common denominator between the fractions, we can multiply the whole equation by s(s-5):
If we rearrange this, we can turn it into a quadratic equation and factor:
Technically, either of these solutions would work when plugged into the original equation, but I would use the second solution because it's a little "neater." We have the speed for the first part of the trip (9 mph); now we just need to subtract 5mph to get the speed for the second part of the trip.
The canoeist's speed on the first part of the trip was 9mph, and their speed on the second part was 4mph.
Answer:
480 cubic cm.
Step-by-step explanation:
We have been given that a wedge of cheese in he shape of a triangular prism has lengths of 10 cm, 13 cm, and 13 cm for its triangular sides. The perpendicular distance from the 10 cm side to the point of the wedge is 12 cm. The height of the wedge is 8 cm.
We can see from our attachment that base of our triangular face is 10 cm and height of the triangular face is 12 cm and height of wedge is 8 cm.
Substituting these values in volume formula we will get,
Therefore, the volume of cheese wedge will be 480 cubic cm.
