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inessss [21]
2 years ago
8

Can someone help me with this math problem? “Solve the equation for y, if it’s not already solved for. If already solved for, ty

pe already solved.”
the equation: 5x+3y=15
Mathematics
1 answer:
makkiz [27]2 years ago
8 0

Answer:

<u>y=(-5/3x)+5</u>

Step-by-step explanation:

so you want to isolate the variable of y.

5x+3y=15

5x+3y-5x=15-5x

3y=-5x+15

3y/3=(-5x+15)/3

y=(-5/3x)+5

<em>i am in algebra two so you can trust my answer. if you need more help, lmk in the comments. happy holidays and stay safe!</em>

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3 years ago
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The general form of an parabola is 2x2−12x−3y+12=0 .
Murljashka [212]

Answer:

The standard form of the parabola is (x-3)^2=4*\frac{3}{8}(y+2)

Step-by-step explanation:

The standard form of a parabola is

(x-h)^2=4p(y-k).

In order to convert 2x^2-12x-3y+12=0 into the standard form, we first separate the variables:

2x^2-12x+3y+12=0\\\\2x^2-12x+12=3y

we now divided both sides by 2 to remove the coefficient from 2x^2 and get:

x^2-6x+6=\frac{3}{2}y.

We complete the square on the left side by adding 3 to both sides:

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x^2-6x+9=\frac{3}{2}y+3

(x-3)^2=\frac{3}{2}y+3

now we bring the right side into the form 4p(y-k) by first multiplying the equation by \frac{2}{3}:

\frac{2}{3} *(x-3)^2=\frac{2}{3} *(\frac{3}{2}y+3)\\\\\frac{2}{3} *(x-3)^2=y+2

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Thus, finally we have the equation of the parabola in the standard form:

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3 years ago
50 points :)<br> 10x9=??
Marrrta [24]

\\ \sf\longmapsto 10\times 9

\\ \sf\longmapsto 90

Note down below rules for sign notations

  • (-)(-)=(+)
  • (+)(-)=(-)(+)=(-)
  • (+)(+)=(+)
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3 years ago
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