Answer:
the answer is c!
Step-by-step explanation:
Arrange your given equation to resembles the form
a^2 +2ab+ b^2 because this equals (a+b)^2
So we get:
y^2+16y+8^2=0
Now compare
y^2+16y+8^2 to a^2 +2ab+ b^2
So we got
y^2+2•8 y+8^2=0 which equals (y+8)^2
Let the height of the building be x. Let the initial distance of the ant from the building be y, then
tan 32 = x/y
y = x/tan 32 . . . . . . . . (1)
tan 22 = x/(y + 66)
y tan 22 + 66 tan 22 = x
y = (x - 66 tan 22)/tan 22 . . . . . . . . (2)
Equating (1) and (2), we have
x/tan 32 = (x - 66 tan 22)/tan 22
x tan 22 = x tan 32 - 66 tan 22 (tan 32)
x(tan 32 - tan 22) = 66 tan 22 (tan 32)
x = (66 tan 22 (tan 32))/(tan 32 - tan 22) = 66(0.4040)(0.6249)/(0.6249 - 0.4040) = 16.6626/0.2208 = 75.4
Therefore, the height of the building is 75.4 feet.
Answer:
-5
Step-by-step explanation:
20-5m
20-5(5)
20-25
5.
Is this the answer that you are looking for?
$9.78 (5) this is the expression I'm pretty sure that all you need for the answer