Answer:
AC = 8 cm,
AD = 3 cm and ∠ACB = ∠CDA
From figure,
∠CDA = 90°
∴ ∠ACB = ∠CDA = 90°
In right angled ∆ADC,
AC2 = AD2 + CD2
⇒ (8)2 = (3)2 + (CD)2
CD2 = 64 – 9 = 55
⇒ CD = √55 cm
In ∆CDB and ADC.
∠BDC = ∠AD [each 90°]
∠DBC = ∠DCA [each equal to 90°-∠A]
∴ ∠CDB ∼ ∆ADC
Then,
Answer: The required equation is
and the number of fishes in the pond on June 1 = 115
Step-by-step explanation:
Given: The number of fishes in pond on July 1 = 63
Also, it is said that the number of fishes in pond on July 1 is 52 fewer(lesser) than the number of fishes in pond on June 1.
Let f be the number of fishes in pounds on June 1.
then the required equation will be

Now, add 52 on both the sides of the equation, we get

Answer:
I can't see the picture
Step-by-step explanation:
E=9h+1.5(9)(h-40)
e=9h+13.5(h-40), since h=49
e=9(40)+13.5(9)
e=9(40+13.5)
e=9(53.5)
e=$481.50