All categories

3 years ago

3. Solve the following problems. Reminder: Keep track of when you are dealing with part-to-

Mathematics

1 answer:

DIA [1.3K]3 years ago

5 0

Answer:

Out of town teenagers = 30

Step-by-step explanation:

Given that,

Total number of teenagers at a swim meet = 50

Let there are 2x locals and 3x out of town participants. The ratio of locals to out-of-town participants is 2:3.

ATQ,

2x+3x = 50

5x = 50

x = 10

Out of town teenagers = 3x

= 3(10)

= 30

Hence, there are 30 teenagers travelled from out-of-town to the swim meet.

You might be interested in

Susie drew the shape with a perimeter of 36 inches then she drew a square one side of the square was x inches What is the perime

tatuchka [14]

Answer:

Step-by-step explanation:

3 0

3 years ago

Determine whether a figure with the given vertices is a rectangle using the Distance Formula.

Alex Ar [27]

Answer:

Yes; Opposite sides are congruent, and diagonals are congruent.

Step-by-step explanation:

we have

$A(4, -7), B(4, -2), C(0, -2), D(0, -7)$

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the length of the sides

Find the distance AB

substitute the values

$d=\sqrt{(-2+7)^{2}+(4-4)^{2}}$

$d=\sqrt{(5)^{2}+(0)^{2}}$

$AB=5\ units$

Find the distance BC

substitute the values

$d=\sqrt{(-2+2)^{2}+(0-4)^{2}}$

$d=\sqrt{(0)^{2}+(-4)^{2}}$

$BC=4\ units$

Find the distance CD

substitute the values

$d=\sqrt{(-7+2)^{2}+(0-0)^{2}}$

$d=\sqrt{(-5)^{2}+(0)^{2}}$

$CD=5\ units$

Find the distance AD

substitute the values

$d=\sqrt{(-7+7)^{2}+(0-4)^{2}}$

$d=\sqrt{(0)^{2}+(-4)^{2}}$

$AD=4\ units$

Compare the length sides

AB=CD

BC=AD

therefore

Opposite sides are congruent

step 2

Find the length of the diagonals

Find the distance AC

substitute the values

$d=\sqrt{(-2+7)^{2}+(0-4)^{2}}$

$d=\sqrt{(5)^{2}+(-4)^{2}}$

$AC=\sqrt{41}\ units$

Find the distance BD

substitute the values

$d=\sqrt{(-7+2)^{2}+(0-4)^{2}}$

$d=\sqrt{(-5)^{2}+(-4)^{2}}$

$BD=\sqrt{41}\ units$

Compare the length of the diagonals

AC=BD

therefore

Diagonals are congruent

The figure is a rectangle, because Opposite sides are congruent, and diagonals are congruent

8 0

4 years ago

Read 2 more answers

Simplify: (-7x + 5) - (2x2 – 8x + 6). Choose the standard form of the answer.

Tcecarenko [31]

Answer:

A.-2x2+-1

Step-by-step explanation:

(-7x+5)-(2x2-8x+6)

-7x+5-2x2+8x-6 then collect like terms

-2x2-7x+8x+5-6

-2x2-x+1

If it's helpful ❤❤❤

THANK YOU

3 0

3 years ago

ELECTRICITY The impedance in one part of a series circuit is 1 + 3j ohms and the impedance in another part of the circuit is 7 -

TiliK225 [7]

Answer:

Total impedance in circuit = 8 - 2j ohms

Step-by-step explanation:

Given:

Circuit one = 1 + 3j ohms

Circuit two = 7 - 5j ohms

Find:

Total impedance in circuit

Computation:

Total impedance in circuit = Circuit one + Circuit two

Total impedance in circuit = 1 + 3j + 7 - 5j

Total impedance in circuit = 8 - 2j ohms

5 0

3 years ago

Someone help me!! Alegbra 1, I've been stuck on this question for 30 mins now!!

Anastasy [175]

Try your best
a song should cheer you up you got this i know you do

4 0

3 years ago