it hasn't been specified which ticket the question's is asking but I'm guessing the price of the adult ones so $30.00
altogether that's two adults and 3 children who all paid a total of $105.00
let's simplify that to algebra
children tickets = c adults tickets = a
3c + 2a = $105.00
we know that 1c is 0.5a because each child ticket is half of an adults one <em>as stated in the question</em>
so in terms of (adults) a: half of 3 meaning 3×0.5= $1.5 meaning 1.5a
so now <em>3c = 1.5a</em>
so we can substitute and have like terms
meaning 1.5a + 2a= $105
3.5a =$105.00
divide by 3.5 on both sides to get a by itself thus the value of a:
a = $30
so each adult tickets cost $30
We consider the x- and y-coordinates separately. Let the coordinates of G be (x, y). Now considering the x-coordinates:
FG/FH = (x - (-3)) / (-3 - (-3)) = 2/3
x + 3 = (2/3)(6)
x = 1
For the y-coordinates:
FG/FH = (y - 2) / (7 - 2) = 2/3
y - 2 = (2/3)(5)
y = 16/3
Therefore the coordinates of G are (1, 16/3).
Answer:
2 l think
Step-by-step explanation:
Step-by-step explanation:
5*(4x+8)=6*(2x+3)
20x+40=12x+18
20x _12x= 18_40
8x = _22
x=_22/8
x= _11/4
I believe the answer is C
