Answer:
a
b
Step-by-step explanation:
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The distance between them is 4.0
The equation would be 1.5-(-2.5)=d
Hope that helps?
Let x represent amount invested in the higher-yielding account.
We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be 
.
We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.
, where,
I = Amount of interest,
P = Principal amount,
r = Annual interest rate in decimal form,
t = Time in years.
We are told that interest rates are 6% and 10%.
Amount of interest earned from lower-yielding account: 
.
Amount of interest earned from higher-yielding account: 
.
Let us solve for x.
Therefore, the man invested $30,000 at 10%.
Amount invested in the lower-yielding account would be 
.
Therefore, the man invested $60,000 at 6%.
Answer:
**If the interest is by year then this should work
The interest is $15600 and the amount is $80600.
Step-by-step explanation:
Problem
You deposit $65000 into a bank account paying 6% simple interest per year. You left the money in for 4 years. Find the interest earned and the amount at the end of those 4 years?
Result:
The interest is $15600 and the amount is $80600.
Answer:
f^-1(x) = (x/8)^(1/5) is a function
Step-by-step explanation:
The inverse of a function is the function reflected across the line y=x. This results in the coordinate points (x,y) of the function becoming (y,x) for the inverse function. Algebraically to find the inverse, switch the x and y locations and solve for y.
y = 8x^5
x = 8y^5
x/8 = y^5
(5)√(x/8) = y
This is a fifth root of (x/7) also written in exponents as y = (x/8)^(1/5).
This is a function. While it appears not to be a function because the middle portion over the origin appears vertical, it is a function because the middle portion over the origin is changing and graphing software shows it has no input with more than one output. Without graphing software you would rule it is not a function.
