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Natalka [10]
3 years ago
6

Using the given table of an exponential function, determine the growth/decay factor as well as the rate of increase/decrease. Ty

pe your answers in as numbers. Example: Growth Factor: 3.5, Rate of Increase: 2.5. (Do not input your rate of increase as a percent.)

Mathematics
1 answer:
Westkost [7]3 years ago
7 0

Answer:

The growth rate is 0.6

The growth factor is 1.6

Step-by-step explanation:

Generally, the exponential equation can be written as;

y = a(1 + r)^x

Where a is the initial value of 100

r is the growth rate

So let us form equations;

160 = 100(1 + r)^1 •••••(i)

Also;

256 = 100(1 + r)^2 •••••••(ii)

Divide equation ii by i

256/160 = 1 + r

1.6 = 1 + r

r = 1.6-1

r = 0.6

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skelet666 [1.2K]

Answer:

-3x+12-9x+8=-3(4x-7)

-3x+12-9x+8=-12x+21

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hope this helps

have a good day :)

Step-by-step explanation:

6 0
3 years ago
Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De
Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable <em>X</em> represent the time a child spends waiting at for the bus as a school bus stop.

The random variable <em>X</em> is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is,\lambda=\frac{1}{\mu}=\frac{1}{7}.

The probability density function of <em>X</em> is:

f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx

                      =\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

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Step-by-step explanation:

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brainliest pls :D

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