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mel-nik [20]
2 years ago
8

There are two mystery numbers the sum of eight times the first number and 10 times the second number is 24. The sum of seven tim

es the first number and 10 times the second number is 26 what is the two numbers
Mathematics
1 answer:
bonufazy [111]2 years ago
8 0

Answer:

x = the first mystery number = 2

y = the second mystery number = 0.8

Step-by-step explanation:

Let

x = the first mystery number

y = the second mystery number

8*x + 10*y = 24

8x + 10y = 24

7*x + 10*y = 26

7x + 10y = 26

8x + 10y = 24 (1)

7x + 10y = 26 (2)

Subtract (1) from (2) to eliminate y

8x - 7x = 26 - 24

x = 2

Substitute x = 2 into (1)

8x + 10y = 24 (1)

8(2) + 10y = 24

16 + 10y = 24

10y = 24 - 16

10y = 8

y = 8/10

y = 0.8

x = the first mystery number = 2

y = the second mystery number = 0.8

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What decimal represents 6×1,000+2×10+3×1/10+5×1/1,000
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3 years ago
Given the functions, fx) = x - 8 and g(x) = x2 + x - 1, perform the indicated operation. When applicable, state the domain
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Answer:

A

Step-by-step explanation:

(fg)(x) = f(x) × g(x)

= (x - 8)(x² + x - 1)

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x(x² + x - 1) - 8(x² + x - 1) ← distribute both parenthesis

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4 0
3 years ago
a toy manufacturer has designed a new piece for use in building models. It is a cube with side lengths 7 mm and has a 3 mm in di
Ray Of Light [21]

Given that the cubical piece has side (s) 7 mm, and a cylindrical hole of diameter (d) as 3 mm.

The volume of the piece can be calculated as,

\begin{gathered} \text{Volume of piece}=\text{ Volume of cube}-\text{ Volume of cylinder} \\ V=s^3-\frac{\pi}{4}d^2s \\ V=7^3-\frac{\pi}{4}(3)^2(7) \\ V=343-\frac{63\pi}{4} \\ V\approx293.52mm^3 \\ V\approx293.52\times10^{-9}\text{ }m^3 \end{gathered}

It is mentioned that the material costs $207 per cubic meter, so the cost (c) of 1 piece is calculated as,

\begin{gathered} \text{Cost of 1 piece}=\text{ Cost per unit volume}\times\text{ Volume of 1 piece} \\ c=207\times293.52\times10^{-9} \\ c\approx60758.64\times10^{-9} \end{gathered}

This is the cost (in dollars) for 1 piece.

Given that the manufacturer wants to produce 1,000,000 such pieces, so the total cost (TC) is calculated as,

\begin{gathered} \text{Total Cost}=\text{ Cost per piece}\times\text{ No. of pieces} \\ TC=60758.64\times10^{-9}\times1,000,000 \\ TC=60758.64\times10^{-9}\times10^6 \\ TC=60758.64\times10^{-3} \\ TC=60.75864 \\ TC\approx60.75 \end{gathered}

Thus, the total prototypes will cost around $60.75

7 0
1 year ago
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