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alina1380 [7]
3 years ago
10

89 m 80 m What is the length of the missing leg

Mathematics
1 answer:
sergiy2304 [10]3 years ago
6 0

Answer:

119.67

Step-by-step explanation:

a^2 + b^2 =c^2

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3. Given 4x – 8y = 8:
Mazyrski [523]
Slope-intercept form is y = mx + b, so to turn that equation into slope-intercept you'll need to get y alone

4x - 8y = 8 --- subtract 4x
-8y = 8 - 4x --- divide by -8
y = -1 + (1/2)x --- reorder to match "mx + b"
y = (1/2)x - 1

in y = mx + b, "m" is the slope and "b" is the y-intercept. so for part B, your slope is (1/2) and your y-intercept is (-1). take the sign with you.

for part C, you'll need to know point-slope form: (y - y1) = m(x - x1)
you'll also need to be aware that "perpendicular" lines have a slope that is the opposite reciprocal of the original line.

the original slope is (1/2). change the sign to negative and form a reciprocal: your new slope is -2. plug that into your point-slope form

(y - y1) = m(x - x1)
(y - y1) = (-2)(x - x1)

and lastly, plug in your given point: (1, 2)

y - 2 = (-2)(x - 1)

so, just to look a little neater without all of the work:
A) y = (1/2)x - 1
B) m = (1/2), b = -1
C) y - 2 = (-2)(x - 1)
5 0
3 years ago
Help this sleep deprived goth pleas!!
kap26 [50]

Answer:

the slope of the equation is -5 and the y-intercept is +3

Step-by-step explanation:

sorry but i cannot graph it for you

4 0
3 years ago
Read 2 more answers
How are these two problem different 35-15 and 43-26
Anna35 [415]
Wne solved they have different answers 

35 - 15 = 20
       and
43 - 26 = 17
4 0
3 years ago
PLEASE HELLLLLPPPPPPP
NARA [144]
Its D. 3.7 units long
5 0
4 years ago
Read 2 more answers
Which function has an inverse that is also a function? a {(–1, 3), (0, 4), (1, 14), (5, 6), (7, 2)} b {(–1, 2), (0, 4), (1, 5),
ivanzaharov [21]
An expression, that is a function, will have no x-repeats on the x,y pairs.

and expression that is a function, and has an inverse that is also a function, will have no x-repeats, and no y-repeats either, so the pairs will be unique for the set, let's do some checking then,

\bf a \qquad\{(-1, 3), (0, 4), (1, 14), (5, 6), (7, 2)\}\\\\
b \qquad\{(-1, 2), (0, \stackrel{\downarrow }{4}), (1, 5), (5, \stackrel{\downarrow }{4}), (7, 2)\}\impliedby 
\begin{array}{llll}
\textit{notice the } y-rep eats\\
\textit{thus, no dice}
\end{array}

\bf c \qquad\{(-1, -2), (0, \stackrel{\downarrow }{4}), (1, 3), (5, 14), (7, \stackrel{\downarrow }{4})\}\impliedby 
\begin{array}{llll}
\textit{notice the } y-rep eats\\
\textit{thus, no dice}
\end{array}\\\\
d \qquad\{(-1, \stackrel{\downarrow }{4}), (0, \stackrel{\downarrow }{4}), (1, 2), (5, 3), (7, 1)\}\impliedby 
\begin{array}{llll}
\textit{notice the } y-rep eats\\
\textit{thus, no dice}
\end{array}
6 0
4 years ago
Read 2 more answers
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