Negative 1 because 3 x 3 is 9 and -2 x 5 is -10. Therefore 9-10= negative 1
The zeroes are
0, -5, 3 + i (and its conjugate)
The factors are
x (x + 5) (x - (3 + i)) (x - (3 - i))
Expanding...
(x² + 5x)((x - 3) - i) ((x - 3) + i)
(x² + 5x)((x - 3)² - i²)
(x² + 5x)(x² - 6x + 9 - (-1))
(x² + 5x)(x² - 6x + 10)
x⁴ - 6x³ + 10x² + 5x³ - 30x² + 50x
x⁴ - x³ - 20x² + 50x
Answer:
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Answer:
$$$$$$$$ the anwser is 4 i think thats how you solve it
Step-by-step explanation:
