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2 years ago

If f(x)=l 2x-4 l, find f(-7).

Mathematics

1 answer:

Ierofanga [76]2 years ago

7 0

Answer:

f(-7) = 18

Step-by-step explanation:

Add AbS in calculator

2(-7) = -14 (AbS) -> 14

-4 -> (AbS) = 4

14+4 = 18

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Need help for this Algebra question plz!

Vikentia [17]

Answer:

2x+5y=-15

ax+bx=c

slope=-a/b so -2/5 matches up with point slope form

then to get y intercept substitite x in point slope for 0 and solve for Y to get -3

then do c/b to get y intercept, so -15/5, which equals -3.

5 0

3 years ago

Find f(-2) for the following function. f(x)=3.6x-2

butalik [34]

Answer:

f(- 2) = - 9.2

Step-by-step explanation:

To evaluate f(- 2) substitute x = - 2 into f(x) , that is

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3 years ago

Suppose y varies directly as x and y=36 when x=4 find y when x=11

yarga [219]

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3 years ago

Find m A. 40° B. 80° C. 130° D. 260°

alekssr [168]

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3 years ago

Read 2 more answers

Lim t^4 - 6 / 2t^2 - 3t + 7

Harman [31]

I think you meant to say

$\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}$

(as opposed to x approaching 2)

Since both the numerator and denominator are continuous at t = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

$\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}$

Because these expressions are continuous at t = 2, we can compute the limits by evaluating the limands directly at 2:

$\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}$

6 0

3 years ago