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makkiz [27]
2 years ago
15

If f(x)=l 2x-4 l, find f(-7).

Mathematics
1 answer:
Ierofanga [76]2 years ago
7 0

Answer:

f(-7) = 18

Step-by-step explanation:

Add AbS in calculator

or

2(-7) = -14 (AbS) -> 14

-4 -> (AbS) = 4

14+4 = 18

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Philip and Kevin are hoping to earn enough money to buy concert tickets for a show that costs $225 her concert tickets. Philip a
Zigmanuir [339]

Answer:

Kevin is going to be able to have enough money for the concert the fastest

Philip needs at least 4 weeks

Kevin needs at least 3 weeks

Step-by-step explanation:

<u>Philip</u>

  • $8.75/hour * 6 hours/weekend * 1 weekend/week = $52.5/week
  • $45 saved

Let's call x to the number of weeks Philip needs to reach $225.

52.5*x + 45 = 225

52.5*x = 225 - 45

x = 180/52.5

x = 3.43

He needs at least 4 weeks

<u>Kevin</u>

  • 3 hours/day * $7.5/hour *3 days/week = $67.5/week
  • $30 saved

Let's call y to the number of weeks Kevin needs to reach $225.

67.5*y + 30 = 225

67.5*y = 225 - 30

y = 195/67.5

y = 2.9

He needs at least 3 weeks

6 0
3 years ago
The diameter of the planet Mercury is 4.87×103 kilometers. The diameter of the planet Venus is 1.21×104kilometers. The diameter
kow [346]

Answer: Venus

Step-by-step explanation:

5 0
2 years ago
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What the answer to this
alisha [4.7K]

Answer:

Grapes are sold for 1.75 per pound.

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3 years ago
A music store is having a sale where you can buy 2 new-release CDs for $15. How much will 7 CDs cost? Use at least 2 ways to sho
Pavlova-9 [17]

Answer: $52.50

Step-by-step explanation:

1 way : 15 divided by 2 then multipy your answer by 7

2nd way : 15x7. Once you get that answer divide it by 2 to get $52.50

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3 years ago
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Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are
Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

.

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}.

Recall that \binom{n}{k}= \frac{n!}{k!(n-k)!} In this case, the student passes if X is at least four correct questions, then

P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696

c)The expected value of a binomial random variable with parameters n and p is E[X] = np. IN our case, n=6 and p =0.2. Then the expected value of correct answers is 6\cdot 0.2 = 1.2

5 0
3 years ago
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