Suppose that (x,3/5) is a point in quadrant 2 lying on the unit circle.
1 answer:
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L=2w-3
w(2w-3)=54
2w²- 3w-54=0
A= 2 , B= -3, C= -54
sub values into quadratic formula
i attached picture of formula
Final answer: you will be given 2 answers 6 and -4.5. -4.5 is rejected since a negative value cannot represent length because that just doesn't make sense.
w=6
Check:
L=2w-3
=2(6)-3
=12-3
=9
9*6=54
Therefore the dimensions of the photograph are 6 cm by 9 cm
w(2w-3)=54
2w²- 3w-54=0
A= 2 , B= -3, C= -54
sub values into quadratic formula
i attached picture of formula
Final answer: you will be given 2 answers 6 and -4.5. -4.5 is rejected since a negative value cannot represent length because that just doesn't make sense.
w=6
Check:
L=2w-3
=2(6)-3
=12-3
=9
9*6=54
Therefore the dimensions of the photograph are 6 cm by 9 cm