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3 years ago

How do you use the order of operations to evaluate expressions with exponents?

1 answer:

5 0

Using BEDMAS, it would be brackets first, so anything Inside a set of brackets would be solved first, and would follow the same rule. Once the brackets have been solved, next would be the exponents. Since your brackets have been solved you can expand with the exponents. After exponents, would be anything that has to be divided or multiplied. These two operations are interchangeable based on what is more convenient or beneficial to do first. And lastly, addition and subtraction, which once again are interchangeable operations

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Maria mixed a purple paint color using 5 tubes of blue and 7 tubes of red to create one painting. How many tubes of red paint wo

saveliy_v [14]

Answer:

Step-by-step explanation:

because it took 7 tubes of red for one painting and when she does 6 you would multiply 6x7 and it would equal 42.

5 0

3 years ago

WILL GIVE BRAINLIEST!

andreev551 [17]

Answer:

1,632(

Step-by-step explanation:

I did 34,284/252 to figure out the # of groups with 252 people

I got 136.04-- rounded it to 136

I then multiplied 136*12=1,632

so 1,632 people have type A blood

3 0

3 years ago

Read 2 more answers

A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021

egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

$\displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}$

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

$\displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}$

Therefore, for the last term we have;

$\displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}$

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

$\displaystyle \frac{A}{2} = \mathbf{ 1011 \cdot \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460} \right)}$

$\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2} +\frac{1}{2} - \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022} \right)$

Which gives;

$\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2022} \right)$

$\displaystyle A = 2 \times 1011 \cdot \left(1 - \frac{1}{2022} \right) = \frac{1032231}{511} \approx \mathbf{2020.022}$

A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0

2 years ago

Read 2 more answers

Write the standard form of 1x1/10 + 8x1/100

alisha [4.7K]

We are given the expanded form and we need to write the standard form:
10 + 8x(1/10) + 3 x(1/100) + 9 x (1/1000)
So, that is:
10 + 0.8 + 0.03 + 0.009
= 10.839

6 0

3 years ago

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Calculate the interest earned and total amount of money for the following: 1. Principal: $4,500 Interest: 7% 2. Principal: $1,50

Dafna11 [192]

I forgot how to do this sorry.

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3 years ago