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BaLLatris [955]
3 years ago
5

VERY EASY, WILL GIVE 50 POINTS FOR CORRECT ANSWER ASAP AND WILL GIVE BRAINLIEST.

Mathematics
1 answer:
Tema [17]3 years ago
6 0

Answer:

ABCD is reflected over both axes

Step-by-step explanation:

I got it right on my quiz

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Select the place the symbol that will make the statements true -|y| __ |-y|
Genrish500 [490]
The symbol that will make that statement true is <
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Who needs pts.<br> Look for my next question... ill be giving a free 100pts
IRISSAK [1]

Answer:

ok

Step-by-step explanation:

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3 years ago
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Find the hypotenuse of each isosceles right triangle when the legs are of the given measure. 6 sqrt 2
Gemiola [76]
Isosceles right triangles have two equal sides (a and b) that are not the hypotenuse (c). And when two sides are equal, so are their opposite angles. There are only 180° degrees in any triangles, thus the right angle = 90°, so 90 left for the two equal, means that 2x=90,
x = 45°.

There are several ways to go about solving a triangle like this. The best and easiest is simply to memorize that the hypotenuse is exactly root2 times the other sides. Or, each isosceles side is the hypotenuse (c) ÷ root2
a = b = c \div  \sqrt{2} \\ c  = a\sqrt{2}  \\ c = 6 \sqrt{2} \times \sqrt{2}  = 6 \times 2 = 12
Another way to do it is the longer proof of Pythagorean Theorem:
{c}^{2}  =  {a}^{2}  +  {b}^{2}... \:  \:  c =   \sqrt{({a}^{2}  +  {b}^{2})}  \\
c= \sqrt{({6 \sqrt{2}) }^{2} + ({6 \sqrt{2})}^{2}}  \\ =  \sqrt{(2 \times{(6 \sqrt{2} )}^{2} )}  =  \sqrt{2(36 \times 2)}  \\ c =  \sqrt{144}  = 12

7 0
3 years ago
a walking path across a park is represented by the equation y=-2x-7. A new path will be built perpendicular to this path.The pat
jonny [76]

Answer:

The equation that represents the new path is y=(1/2)x-2

Step-by-step explanation:

step 1

Find the slope of the give line

we have

y=-2x-7

so

the slope m is equal to

m=-2

step 2

Find the slope of the perpendicular line to the given line

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal of each other

so

we have

m=-2 -----> slope of the given line

therefore

The slope of the perpendicular line is equal to

m=1/2

step 3

With m=1/2 and the point (-2,-3) find the equation of the line

y-y1=m(x-x1)

substitute

y+3=(1/2)(x+2)

y=(1/2)x+1-3

y=(1/2)x-2 -----> equation that represent the new path

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2. solve 4w − 7k = 28 for k. show your work
NISA [10]
4w-7k=28
-7k+4w+-4w=28+-4w
-7k=-4w+28
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:)
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