Find the measure of each missing angle.

Mathematics

1 answer:

maria [59]2 years ago

8 0

Answer:

<1=63°

<2=49°

<3=87°

<4=44°

Step-by-step explanation:

<1=180-68-49=63°

<2=49°

<3=180-93=87°

<4=180-49-87=44°

You might be interested in

In ΔEFG, e = 8.9 cm, f = 7.7 cm and g=2.2 cm. Find the measure of ∠F to the nearest degree.

Setler79 [48]

Answer:

51 degrees

Step-by-step explanation:

gave up on delta math

7 0

2 years ago

Describe the main parts of a proof

uysha [10]

Show how you got your answer in reverse. For example... if ur question is
4+4/(?)=4
8/?=4
oh its commen sense that the answer is 2.
now show how u got the answer 2.

? is 2 because, 4 times 2 equals 8
4(2)=8

6 0

2 years ago

Root 3 cosec140° - sec140°=4 prove that

Lorico [155]

Answer:

Step-by-step explanation:

We are to show that $\sqrt{3} cosec140^{0} - sec140^{0} = 4\\$

Proof:

From trigonometry identity;

$cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}$

$\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\$

From trigonometry, 2sinAcosA = Sin2A

$= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\= \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2 \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}$