1. D
2. A
3. C
Question 2 MIGHT be D, but I think it's A
Since the perimeter must not exceed 291.
Let the third side be x.
x + 87 + 64 < 291
x + 151 < 291.
x < 291 -151.
x < 140. (First)
But for a triangle there is what is called the Triangle Inequality Theorem. That given the two sides of a tringle, the third side of the triangle must greater than the positive difference between the two sides and less than the sum of the two sides.
So for this case. 87 and 64.
x > ( 87 - 64). x > 23.
x < (87 + 64) x < 151. Combine both inequalities.
23 < x < 151 (second).
Combining First and second. Both must be satisfied.
So we have a more accurate answer as:
23 < x < 140. x is greater than 23 and x is less than 140.
x could be 24, 25, 26, 27, ......, 139. cm.
I hope this helps.
Answer:
Make a coordinate plane and you have to solve around the origin say 4,4 and 4,1.
Step-by-step explanation:
Answer:
The statement is false.
Step-by-step explanation:
A parallelogram is a figure of four sides, such that opposite sides are parallel
A rectangle is a four-sided figure such that all internal angles are 90°
Here, the statement is:
"A rectangle is sometimes a parallelogram but a parallelogram is always a
rectangle."
Here if we found a parallelogram that is not a rectangle, then that is enough to prove that the statement is false.
The counterexample is a rhombus, which is a parallelogram that has two internal angles smaller than 90° and two internal angles larger than 90°, then this parallelogram is not a rectangle, then the statement is false.
The correct statement would be:
"A parallelogram is sometimes a rectangle, but a rectangle is always a parallelogram"
Answer:
7
Step-by-step explanation:
(+8)-(-4)+(-5)
8+4-5
12-5
7
