Answer:
Given that is a 45-45 triangle, the hypotenuse should be <em>x</em>
, so in this case. The hypotenuse should be 3
, and the other side lengths 3. I see no other way of it going other than that one; I hope I helped at least a bit!
Step-by-step explanation:
7 goes into 11 one time, which leaves you with 1 4/7.
Answer:
2 ( x+3) (x+1)
Step-by-step explanation:
2x^2+8x+6
Factor out a 2
2(x^2 +4x+3)
Factor in side the parentheses
What multiply to 3 and adds to 4 (3(1=3 3+1 =4)
2 ( x+3) (x+1)
<u>Answer-</u>
<em>The area of QRS is </em><em>238.7</em><em> sq units.</em>
<u>Solution-</u>
According to properties of supplementary angles,
![m\angle R+124=180\\\\m\angle Q+132=180](https://tex.z-dn.net/?f=m%5Cangle%20R%2B124%3D180%5C%5C%5C%5Cm%5Cangle%20Q%2B132%3D180)
So,
![\Rightarrow m\angle R=180-124=56,\ m\angle Q=180-132=48](https://tex.z-dn.net/?f=%5CRightarrow%20m%5Cangle%20R%3D180-124%3D56%2C%5C%20m%5Cangle%20Q%3D180-132%3D48)
As the sum of measurement of all the angles in a triangle is 180, so
![\Rightarrow m\angle S+m\angle R+m\angle Q=180](https://tex.z-dn.net/?f=%5CRightarrow%20m%5Cangle%20S%2Bm%5Cangle%20R%2Bm%5Cangle%20Q%3D180)
![\Rightarrow m\angle S=180-m\angle R-m\angle Q](https://tex.z-dn.net/?f=%5CRightarrow%20m%5Cangle%20S%3D180-m%5Cangle%20R-m%5Cangle%20Q)
![\Rightarrow m\angle S=180-56-48=76](https://tex.z-dn.net/?f=%5CRightarrow%20m%5Cangle%20S%3D180-56-48%3D76)
Then the area of the triangle will be,
![\text{Area}=\dfrac{1}{2}qr\sin S](https://tex.z-dn.net/?f=%5Ctext%7BArea%7D%3D%5Cdfrac%7B1%7D%7B2%7Dqr%5Csin%20S)
![=\dfrac{1}{2}\times 21\times 23.43\times \sin 76](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%2021%5Ctimes%2023.43%5Ctimes%20%5Csin%2076)
![=238.7\text{sq.units}](https://tex.z-dn.net/?f=%3D238.7%5Ctext%7Bsq.units%7D)