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WARRIOR [948]
3 years ago
8

During March, Pendergraph Corporation incurred $65,000 of actual Manufacturing Overhead costs. During the same period, the Manuf

acturing Overhead applied to Work in Process was $67,000. The journal entry to record the application of Manufacturing Overhead to Work in Process would include a:
Business
1 answer:
Yanka [14]3 years ago
5 0

Answer: Credit to manufacturing overhead of $67000.

Explanation:

The journal entry to record the application of Manufacturing Overhead to Work in Process would be:

Debit Work in Progress $67000

Credit Manufacturing overhead $67000.

( To record the application of manufacturing overhead to work in process).

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Automobile repair costs continue to rise with the average cost now at $367 per repair.† Assume that the cost for an automobile r
vovikov84 [41]

Answer:

a)  0.1728

b)  0.09183

c) 0.7354

d) $ 222.25

Explanation:

Given

mean = \mu = $367

Standard deviation = \sigma =$88

Cost of automobile repair is normally distributed.

a) We have to find P( x > 450 )

P( x > 450 ) = 1 - P( x <= 450 )

Using excel function,   P( x <= x ) = NORMDIST (x,  \mu, \sigma, 1 )

P( x > 450 )   = 1 - NORMDIST( 450 , 367, 88, 1 )

= 1 - 0.8272 = 0.1728

P( x > 450 ) = 0.1728

b)  P( x < 250 ) = NORMDIST( 250 , 367, 88, 1 ) = 0.09183

P( x < 250 ) = 0.09183

c) P( 250 < x < 450 ) = P( x <450 ) - P( x < 250 )

P( x <450 ) = NORMDIST( 450 , 367, 88, 1 ) = 0.8272

P( x < 250 ) = NORMDIST( 250 , 367, 88, 1 ) = 0.09183

P( 250 < x < 450 ) = 0.8272 - 0.09183 = 0.7354

P( 250 < x < 450 ) = 0.7354

d) We have P( X < a ) = 0.05

We have to find a.

Using Excel, = NORMINV ( Probability, \mu, \sigma )

a = NORMINV ( 0.05 , 367, 88 ) = 222.2529

Cost = $ 222.25

8 0
3 years ago
Please answer asap NO LINK PLS
Fynjy0 [20]
Thanks you for helping me with the link
8 0
3 years ago
Lowe’s learned that 25 percent of the time its customers buy a garden hose, they also purchase a sprinkler. Patterns and relatio
podryga [215]

Answer: Data mining

Explanation: Patterns and relationships as indicated are discovered through a technique known as data mining, which is defined as the use of a variety of statistical analysis tools in marketing research to uncover previously unknown patterns in data or relationships among variables. It is also given as a technique for searching large scale databases for patterns; used mainly to find previously unknown correlations between variables that may be commercially useful.

3 0
3 years ago
Read 2 more answers
Hybrid cars are touted as a "green" alternative; however,the financial aspects of hybrid ownership are not as clear. Consider th
lord [1]

Answer:

a)

the hybrid model initially costs $5,200 more than the regular model, plus you have another $330 in extra ownership costs per year. If you plan to own the hybrid car for 6 years, then you must recoup $5,200 / 6 = $866.67 + $330 = $1,196.67 per year.

the cost of driving 1 mile with the hybrid car = $3.60 / 27 = $0.1333

the cost of driving 1 mile with the regular model = $3.60 / 19 = $0.1895

you will save = $0.0562 per mile driven

you would need to drive $1,196.67 / $0.0562 = 21,293 miles per year to make the decision worth it

b)

if you only drive 15,500 miles per year, then you would need to save $0.0772 per mile

that would only result if gasoline's price was:

x/19 - x/27 = 0.0772

0.0526x - 0.037x = 0.0772

0.0156x = 0.0772

x = 0.0772 / 0.0156 = $4.95 per gallon

c)

you must first determine the present value of all additional expenses related to purchasing a hybrid:

year         cash flow

0                -5,200

1                 -330

2                -330

3                -330

4                -330

5                -330

6                -330

Using a financial calculator, the PV = -$6,637.24

now we must use an annuity formula to determine the annual savings required using a 10% discount rate and 6 periods:

annual savings = $6,637.24 / 4.3553 (PV annuity factor, 10%,  6 periods) = $1,523.95

so you must save $1,523.95 per year and that is equivalent to $1,523.95 / $0.0562 = 27,116.47 = 27,116 miles

d)

you also need to save $1,523.95, but you only drive 15,500 miles, so the savings per mile = $0.0983

x/19 - x/27 = 0.0983

0.0526x - 0.037x = 0.0983

0.0156x = 0.0983

x = 0.0983 / 0.0156 = $6.30 per gallon

5 0
3 years ago
When does a business make a profit?<br> A business makes a profit when its exceed its .
Rasek [7]

Answer:

when sales revenue exceed costs

Explanation:

8 0
3 years ago
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