N+(n+1)+(n+2)+(n+3)+(n+4)+(n+5)=270
We use these terms to represent the first six consecutive integers in the sequence
Now we group like terms:
6n+15=270
Minus 15 from both sides of the equation
6n=255
n=42.5 which is not an integer
Is this a joke question?
Besides that, the 2nd number will be 43.5
Answer:
x=3,5
Explanation:
x2−8x+15=0
Try to express the terms of the equation in square form.
Adding 16 both sides of the equation,
(x2−2⋅x⋅4+42)+15=16
or,(x−4)2+15−16=0
or,(x−4)2−1=0
or,(x−4)2−12=0
This is the a2−b2=(a+b)(a−b)form.
(x−4+1)(x−4−1)=0
or,(x−3)(x−5)=0
Now, equate both the terms to zero since both of them when multiplied, give zero.
Either,
x−3=0
∴x=3
Or,
x−5=0
∴x=5
Ans:x=3,5 Hope this helpsXD...!!
Slope = (2+5)/(-3-1) = 7/-4 = -7/4
answer is B -7/4
The denominator( s ) we are given are 
, and . The first thing we want to do is factor the expressions, to make this easier -
This expression is a perfect square, as ( x )^2 = x^2, ( 2 )^2 = 4, 2 * ( x ) * ( 2 ) = 4x. Thus, the simplified expression should be the following -
The other expression is, on the other hand, not a perfect square so we must break this expression into groups and attempt factorization -
Combining ( x + 2 )^2 and ( x + 2 )( x + 3 ), the expression that contains factors of each is ( x + 2 )^2 * ( x + 3 ), or in other words the LCM.
<u><em>Solution = </em></u>
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Answer:
4.1
Step-by-step explanation:
5^2 + (2*8) / (2*2) + 3*3
25 + 16 / 4 + 6
41 / 10
4.1
