<h3>
Answer: Choice A) y = -10x^2</h3>
Explanation:
The equation y = ax^2+bx+c has the value of 'a' determine how wide or narrow the graph is. The closer 'a' is to zero, then the wider it gets; while the further 'a' is from 0, the narrower it gets.
What we need to do is look for equations in which the 'a' value is furthest from 0. In this case, it's with y = -10x^2 since a = -10 is furthest from zero compared to a = -0.9 and a = 9. Set up a number line to help see this. You can also use absolute values to get the job as well.
Therefore, y = -10x^2 has the most narrowest graph.
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
sq. units.
Answer:
975 tickets
Step-by-step explanation:
1200 + 750 =1950/8 = 975
<span>P=2,500</span><span>females=f</span><span>males=f+<span>240</span></span>
This advice is based upon your knowing the first ten or so perfect squares: {1, 4, 9, 16, ... } and their square roots. For example, the sqrt of 16 is 4.
I'd take the given number and determine where it stands among this list of perfect squares. For example, 20 would be between perfect squares 16 and 25.
We could surmise that the sqrt of 20 would be betwen the square roots of 16 and 25, which are, of course, 4 and 5.
We could do a bit better at estimating the sqrt of that number by interpolation. Note that sqrt(20) is closer to 4 than to 5. We could then surmise that the sqrt of 20 is a bit closer to 4 than to 5, e. g., sqrt(20) is approximately 4.4.
Using a calculator as a check: sqrt(20)= 4.47. Thus, our estimate was a bit on the low side: 4.4 instead of 4.47.
