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Mrac [35]
3 years ago
11

Need help ASAP Question 1 of 10

Mathematics
1 answer:
Ulleksa [173]3 years ago
5 0

Answer:

4(x - 9)^2 - 17

Step-by-step explanation:

A horizontal shift to the right by 9 changes x^2 to (x - 9)^2.

A vertical shift down by 1 changes - 16 to -17.

Therefore, the new equation is:

4(x - 9)^2 - 17

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How do i do this?????????
Gnom [1K]

Answer:

x≥5

Step-by-step explanation:

-1 ≥ x/-5

x/-5 ≤ -1

x(-1)/5 ≥ (-1) (-1)

x/5 ≥ 1

5x/5 ≥ 1 ×5

x ≥ 5

I'm not sure but I tried.

For the graph: you can draw a line about 15cm, put 0 at the start then after 5cm put 5 then 10 at 10cm and 15 at the end. At 5 put • that's the starting and go all the way to 15 and add > to show that the line continues. I'm not good at explaining but I hope it helps.

8 0
3 years ago
Factor the GCF: 21x3y4 + 15x2y2 − 12xy3.
-Dominant- [34]
Ugh, these questions.

21x^3y^4 + 15x^2y^2 - 12xy^3

3xy^2 (7x^2y^2 + 5x - 4y)

Clearing up clutter...

3xy² (7x²y² + 5x - 4y)

That's your answer.  Thanks for working my brain. ;)
6 0
3 years ago
Read 2 more answers
When the event is 1/9, the complement of the event is
mamaluj [8]

Answer:

\frac{8}{9}

Step-by-step explanation:

Complement of the event

= 1 -  \frac{1}{9}  \\  =  \frac{9 - 1}{9}  \\  =  \frac{8}{9}  \\

8 0
3 years ago
Solve for w<br> 7=-4w+7<br> w=
devlian [24]

Answer:

0

Step-by-step explanation:

If I'm not mistaken, the answer must be 0.

7-7 is 0, that cancels out

0 divided by -4w is zero. That leaves w alone

w=0. I think that's the answer.

5 0
3 years ago
In Figure 1, the area of square A is 9 square units, the area of square B is 16 square units, and the area of square C is 25 squ
weqwewe [10]

Answer:

C. The sum of the areas of the two smaller squares is equal to the area of the larger square.

Step-by-step explanation:

9 + 16 = 25

36 + 64 = 100

25 + 144 = 169

The relations "less than" and "greater than" can be ruled out. These observations are consistent with selection C.

The triangle area is half the product of the square roots of the squares on the legs, so the areas of the triangles are (respectively) 6, 24, 30. These are not related to the sum of the smaller squares, so the last selection can also be ruled out.

7 0
3 years ago
Read 2 more answers
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