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2 years ago

Which value is the solution of the equation 8.25r = 554.4?

Mathematics

2 answers:

jolli1 [7]2 years ago

5 0

Answer:

R=67.2

Step-by-step explanation:

8.25r=554.4

divide 8.25 from both sides

r=554.4/8.25=67.2

so, r=67.2

zloy xaker [14]2 years ago

4 0

Answer:

r = 67.2

Step-by-step explanation:

Step 1: Solve

Use reverse operations to solve for 'r'

$8.25r=554.4\\\frac{8.25r}{8.25}=\frac{554.4}{8.25}\\r=67.2$

Step 2: Therefore Statement

Therefore 'r' is equal to 67.2

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3 years ago

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Answer:

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3 years ago

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A robot that makes _/6 of a boat per day will make 5 boats in 6 days

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3 years ago

1. Given points A(3, -5) and B(19, -1), find the coordinates of point C that sit 3/8 of the way along line AB, closer to A than

zaharov [31]

1. C(x, y) = (7.3, –3.9)

2. C(x, y) = (17, –1.5)

Solution:

Question 1:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction $\frac{3}{8}$ .

Point divides segment in the ratio formula:

$$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)$

Here, $x_1=3, y_1=-5, x_2=19, y_2=-1$ and m = 3, n = 8

$$C(x, y)=\left(\frac{3\times19+8\times3}{3+8} , \frac{3\times(-1)+8\times(-5)}{3+8}\right)$

$$=\left(\frac{57+24}{11} , \frac{-3-40}{11}\right)$

$$=\left(\frac{81}{11} , \frac{-43}{11}\right)$

C(x, y) = (7.3, –3.9)

Question 2:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction $\frac{3}{8}$ .

Point divides segment in the ratio formula:

$$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)$

Here, $x_1=3, y_1=-5, x_2=19, y_2=-1$ and m = 7, n = 1

$$C(x, y)=\left(\frac{7\times19+1\times3}{7+1} , \frac{7\times(-1)+1\times(-5)}{7+1}\right)$

$$=\left(\frac{133+3}{8} , \frac{-7-5}{8}\right)$

$$=\left(\frac{136}{8} , \frac{-12}{8}\right)$

C(x, y) = (17, –1.5)

8 0

3 years ago

Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5

Minchanka [31]

Answer:

J (6,2) K (2,2)

Step-by-step explanation:

Now distance of AB = [(y2-y1)^2 + (x2-x1)^2]^(1/2)

= 8 units

CB = [(y2-y1)^2 + (x2-x1)^2]^(1/2)

= 6 units by using same formula

Now AB/CB must equal to GH/HJ as rectangles are similar

GH = [(y2-y1)^2 + (x2-x1)^2]^(1/2)

= 4 units

8/6 = 4/HJ

So,

HJ = 3 units

Now if we see the coordinates given carefully, it is obvious that two perpendicular lines lie perfectly parallel to x and y coordinates in rectangle ABCD. A is (-7,-2) and B is (1,-2) which means distance along y-axis doesn't change. Similarly for C (1,-8) and D (-7,-8), one can see that distance between y-axis doesn't change. So lines AB and CD of rectangle are parallel with x and AD and BC are parallel with y-axis.

In rectangle GHJK one can see that in given coordinates, G(2,5) and H(6,5), y coordinate is same so it is parallel to x axis. Now, HJ is perpendicular to GH so it must be parallel to y axis. It means if we know the lengths of sides we can easily determine unknown coordinates by simple addition and subtraction.

So, we know HJ = 3 units

J is (6,2) since HJ is parallel to y axis so distance on x axis will remain unchanged and length of line HJ will effect distance of y axis.

Similarly K is (2,2) for the same reason.

6 0

3 years ago