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Likurg_2 [28]
3 years ago
15

Midpoint question......

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
7 0

Answer:

24; 12; 35

Step-by-step explanation:

Midsegments are 1/2 or their parallel line, so:

SU*2=QR

QR=24

Since QT is half of QR because point T is the midpoint of that line:

SU*1=QT

QT= 12

If PR=70, then ST is half of that:

70/2=35

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Step-by-step explanation:

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3 years ago
"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen
Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }]

Where

p' is the sample proportion/point estimator of the population proportion

Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} } is the margin of error (d) of the confidence interval.

Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648

So

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }

(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}

n*(d*Z_{1-\alpha /2})^2= p'(1-p')

n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}

n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}

n= 147.28 ≅ 148 boxes.

I hope it helps!

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A tiny but horrible alien is standing at the top of the Eiffel Tower (which is 324324324 meters tall) and threatening to destroy
DedPeter [7]

Answer:

A tiny but horrible alien is standing at the top of the Eiffel Tower (which is 324 meters tall) and threatening to destroy the city of Paris! A Men In Black agent is standing at ground level, 54 meters across the Eiffel square, aiming his laser gun at the alien. At what angle, in degrees, should the agent shoot his laser gun? Round your final answer to the nearest tenth

The agent shoot his laser gun at 80.5 degree.

Step-by-step explanation:

Given:

Height at which the horrible alien is standing = 324 m

Distance from the (tower) where the agent is = 54 m

According to the question:

Men In Black agent is aiming his laser gun to shoot the horrible alien.

Let the angle at which the agent shoot his gun be " Ф "

As from the situated depicted we can draw a right angled triangle.

Using trigonometric ratios:

tan (Ф) = opposite/ adjacent

In triangle OPQ .

The adjacent side = 54 m

The opposite side = 324 m

⇒ Plugging the values.

⇒ tan(\phi) = \frac{opposite}{hypotenuse}

⇒  tan(\phi) = \frac{324}{54}

⇒ (\phi) = tan^-^1(\frac{324}{54})

⇒ \phi=80.53

Nearest tenth it is 80.5 degrees.

So,

Men In Black must shoot the laser gun at an angle of 80.5 degrees.

7 0
3 years ago
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