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Ipatiy [6.2K]
3 years ago
10

Kwan bought three rolls of regular wrapping paper with 6.7 square meters of paper each.He also bought a roll of fancy wrapping p

aper containing 4.18 square meters.How much paper did he have altogether?
Mathematics
1 answer:
guajiro [1.7K]3 years ago
5 0

Answer: He had 24.28 m².


Step-by-step explanation:

1. He bought 3 rolls of regular wrapping paper with 6.7 m². Then the total of this paper is:

(3)(6.7m^{2})=20.1m^{2}

2. He also bought a roll of fancy wrapping with 4.18 m². Therefore, to calculate the amount of paper he had together (which you can call x), you must add 20.1 m² and 4.18 m², as you can see below:

x=20.1m^{2}+4.18m^{2}\\x=24.28m^{2}



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Answer:

Which two expressions?

Step-by-step explanation:

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2 years ago
the length of a rectangle is 7 yd less than three times the width, and the area of the rectangle is 66 yd(squared). find the dim
Alex_Xolod [135]
So legnt=l
width=w
l=-7+3w
l=3w-7

area=66
area=legnth times width or
area=lw

subisutte
area=lw
l=3w-7
66=(3w-7)(w)
66=3w^2-7w
subtrac 66 from both sides
0=3w^2-7w-66
factor
HOW TO
multiply 3 and -66=-198
find what 2 numbers add up to -7 and multiply to get -198
the numbers area 11 and -18
so
3w^2-18w+11w-66=0
factor
(3w^2-18w)+(11w-66)=0
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factor using distributive (ab+ac=a(b+c))

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set them to zero
3w+11=0
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3w=-11
legnths cannot be negative so we discard this

w-6=0
add 6
w=6

width=6
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7 0
3 years ago
A 2x2 square is centered on the origin. It is dilated by a factor of 3. What are the coordinated of the vertices of the square?
Alexxx [7]

<u>Answer</u>:

The vertices are:

A' = (-3, -3)

B' = (3, -3)

C' = (3, 3)

D' = (-3, 3)

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<u>Step-by-step explanation:</u>

Given:

A 2 x 2 square is centered at the origin.

So, the center of the square is (0, 0)

Since it is 2 x 2 square, the side of the square is 2 units.

So, the vertices of the 2 x 2 square are A (-1, -1),  B(1, -1), C(1. 1), D(-1, 1)

The above square is dilated by a factor of 3.

Let's name the dilated square A'B'C'D'

To find the coordinates of the vertices of dilated square, we need to multiply each vertices of ABCD by 3.

A(-1, -1) = 3(-1, -1) = A'(-3, -3)

B(1, -1) = 3(1, -1) = B'(3, -3)

C(1, 1) = 3(1, 1) = C'(3, 3)

D(-1, 1) = 3(-1, 1) = D'(-3, 3)

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the side  of the small square is 2 units

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lets find the side AB of the square using distance formula

=>\sqrt{(x_2 -x_1)^2 +(y_2-y_1)^2}

=>\sqrt{(3 - (-3))^2 +(-3 - (-3))^2}

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=>\sqrt{36}

=>6

AB =6 units

In a square all the sides will be equal

Now the area of the larger square will be

6^2

36 square units

The ratio of larger square to smaller square is

=>36 : 4

=>9 : 1

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