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3 years ago

What happens when Earth rotates on its axis and how long does it take

Physics

2 answers:

faust18 [17]3 years ago

8 0

Answer:

You get Day and Night

It takes 24 hour

Luda [366]3 years ago

7 0

Answer:

Explanation:

The Earth's orbit makes a circle around the sun. At the same time the Earth orbits around the sun, it also spins.Since the Earth orbits the sun and rotates on its axis at the same time we experience seasons, day and night, and changing shadows throughout the day.It only takes 23 hours, 56 minutes and 4.0916 seconds for the Earth to turn once on its axis.

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Help? I don't know how to do this.

aliya0001 [1]

Use the definition of acceleration:

Acceleration = (change of velocity) divided by (time for the change)

The graph says:

Change of velocity = -6 m/s

Time for the change = 3 sec

So Acceleration = (-6m/s) / (3 s)

That's -6/3 m/s•s

-2 m/s^2

5 0

4 years ago

Can someone help me with one through seven I will mark you the brainly

ki77a [65]

Answer:

1. F = M x A

2. Force

3. 2nd Law: Force

4. a, b, c (in order)

5. 3rd Law: Action and Reaction

6. b, c, a (in order)

7. 1st Law: Inertia

3 0

2 years ago

Read 2 more answers

What is the average velocity of a car if it travels from position 25m to a position of -7m in 34 seconds?

zubka84 [21]

Answer:

vp = 0.94 m/s

Explanation

Formula

Vp = position/ time

position: Initial position - Final position

Position = 25 m - (-7 m) = 25 m + 7 m = 32 m

Then

Vp = 32 m / 34 seconds

Vp = 0.94 m/s

6 0

3 years ago

Read 2 more answers

A stone is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stopwatch measures the stone's trajec

olga2289 [7]

Answer:

The height of the cliff is 90.60 meters.

Explanation:

It is given that,

Initial horizontal speed of the stone, u = 10 m/s

Initial vertical speed of the stone, u' = 0 (as there is no motion in vertical direction)

The time taken by the stone from the top of the cliff to the bottom to be 4.3 s, t = 4.3 s

Let h is the height of the cliff. Using the second equation of motion in vertical direction to find it. It is given by :

$h=u't+\dfrac{1}{2}gt^2$

$h=\dfrac{1}{2}gt^2$

$h=\dfrac{1}{2}\times 9.8\times (4.3)^2$

h = 90.60 meters

So, the height of the cliff is 90.60 meters. Hence, this is the required solution.

5 0

3 years ago

A car speed off around a bend at a constant 10m/s explain why it's velocity is not constant

VARVARA [1.3K]

It's velocity is not constant as direction is changing.

We know, velocity is speed with direction, so if direction is changing, velocity can't be constant, doesn't matter that speed is constant.

Hope this helps!

8 0

3 years ago