All categories

3 years ago

Find the magnitude and angle of a vector given the components: Bx = 7, By=-5

Physics

1 answer:

Arte-miy333 [17]3 years ago

3 0

Answer:

$|B| = \sqrt{ {B _{x} }^{2} + {B _{y} }^{2} } \\ = \sqrt{ {7}^{2} + {5}^{2} } \\ = \sqrt{74} \\ = 8.6$

$let \: the \: angle \: be \: \theta \\ \tan(\theta) = \frac{B _{y} }{B _{x} } \\ \tan( \theta) = \frac{ - 5}{7} \\ \theta = { \tan }^{ - 1} ( \frac{ - 5}{7} ) \\ = 35.5 \degree$

You might be interested in

Two students are watching a person riding a skateboard up and down a ramp. Each student shares what they think about the energy

Setler79 [48]

Answer:

The correct option is;

Raymond: I think the skateboarder has the same total energy at all points on the ramp

Explanation:

The total energy, also known as the total mechanical energy, is the sum of the kinetic and potential energies of the skateboarder

Given that the potential energy is the energy gained due to elevation, the maximum potential energy is obtained at the top of the ramp, while the maximum kinetic energy, which is the energy due to motion, is at the bottom of the ramp where the skateboarder moves fastest.

However, by the energy conservation principle, the kinetic energy of he skateboarder comes from the conversion of the potential energy, such that the total energy is the same at any particular point on the ramp.

6 0

3 years ago

A frictionless cart of mass M is attached to a spring with spring constant k. When the cart is displaced 6 cm from its rest posi

Marianna [84]

Answer:

Time period of horizontal Oscillation = T = 2 $\pi$ $\sqrt{\frac{m}{k} }$

As you can see, from the equation, Period of oscillation depends upon the mass and the spring constant. Not on the displacement.

Explanation:

Solution:

As we know that:

F = Kx

Here,

K = Spring constant

x = displacement.

First, they are displacing it with 6 cm from its rest position for which Time period of the oscillation is T = 2 seconds.

But next, they want to know the effect on the time period of the oscillation if the displacement x is doubled from 6cm to 12 cm.

First of all, let us see the equation of the time period of the oscillation.

We need to check, if time period does depend on the displacement or not.

As we know,

Time period of horizontal Oscillation = T = 2 $\pi$ $\sqrt{\frac{m}{k} }$

As you can see, from the equation, Period of oscillation depends upon the mass and the spring constant. Not on the displacement.

Since, K is the constant for a particular spring, we need to change the mass of the cart to change the time period.

Hence the Time period will remain same.

8 0

3 years ago

A current of 0.2 A flows through a conductor for 5minutes. How much charge would have passed through the conductor?

Montano1993 [528]

As we know,

$electric \: \: current = \dfrac{charge}{time}$

so, let's solve for charge (q) :

time = 5 minutes = 5 × 60 seconds = 300 seconds.

$0.2 = \dfrac{q}{300}$

$q = 300 \times 0.2$

$q = 60$

hence, the charge = 60 coulombs (C)

4 0

3 years ago

Question 3 of 32

Scorpion4ik [409]

Answer:

the clown can be put on a sealion and the other clown can hold a lot of peole he help a clown that was tall and heivy

Explanation:

3 0

3 years ago

A projectile is shot straight up from the earth's surface at a speed of 10,000 km/hr. how high does it go?

mezya [45]

Naturally we assume that 10000 km/hr is initial velocity (same as being shot from a cannon), and no air resistance. With so high a velocity, the effect of diminishing gravity with increasing radius must be taken into account, so you use an energy solution. M is earth mass, r is earth radius.
KE/m = (9000000/3600)^2/2 = 3858025 J/kg
ΔPE/m = (PE(at height) - PE(at surface))/m = -GM/(r+h) + GM/r
KE/m = ΔPE/m
KE/m - GM/r = -GM/(r+h)
h = -GM / (KE/m - GM/r) - r = 335665.44 m
(Using G = 6.673E-11 Nm^2/kg^2, M = 5.9742E24 kg, r = 6378100 m)

7 0

3 years ago

Find the magnitude and angle of a vector given the components: Bx = 7, By=-5​

Find the magnitude and angle of a vector given the components: Bx = 7, By=-5