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Sati [7]
3 years ago
7

Factorize;

Mathematics
2 answers:
Allushta [10]3 years ago
5 0
A) 2 X 3 + 2 X 5 = 2 (3+5)
B) 5a + 5b - 5c = 5 (a+b-c)
C) ma - ab = a(m-b)
lesya [120]3 years ago
5 0
5.7081 X 10^9    so it would be the ninth power of 10
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If 3x+y=6 what is the of 6x+2y
LuckyWell [14K]

Answer:

12

Step-by-step explanation:

3x + y = 6

Multiply both sides by 2

6x + 2y = 12

4 0
3 years ago
How many three-digit counting numbers are exactly divisible by 6 but not also exactly divisible by 9?
skelet666 [1.2K]
There are ⌊ 999 6 ⌋ − ⌊ 99 6 ⌋ numbers between 100 and 999 (i.e. three digit numbers) which are divisible by six.
3 0
3 years ago
Read 2 more answers
What is the slope of a line that contains points (-10, 7) and (-10, 0)?
seraphim [82]

Answer:

  "undefined"

Step-by-step explanation:

Slope is computed as "rise/run." For the given points, the rise is 7, but the run is 0, so the rise/run is 7/0. Division by zero gives an "undefined" result, so we say the slope is "undefined."

_____

The line is a vertical line: x = -10.

8 0
3 years ago
It's early in the evening, and you're standing in your back yard waiting for the stars to come out. Before long, you can see two
oee [108]
No star is higher; they're the same.
y = 10x + 30
Substitute "9x + 40" with y.

Then you get 9x + 40 = 10x + 30.
Get the variables on one side and the numbers on one side.
Basic algebra used here subtract 9x from both sides. Then subtract 30 from both sides and you will get x = 10.

Plug 10 for X into the equation and you will get Y = 130. Try each problem separately and you will get the same answer for both so they're equal, none is higher.
7 0
3 years ago
15. I had 180 mL of water in a measuring cylinder. I added a stone. The reading is now 195 mL. What is the volume of the stone?​
alexira [117]

Answer: 15 mL

Step-by-step explanation:

Before the stone the reading was 180 mL

When the stone was added the reading rose to 195 mL

So, we subtract them both, this will give us the volume of the stone

195 mL - 180 mL = 15 mL

7 0
3 years ago
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