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olchik [2.2K]
3 years ago
9

Answers for 4 please.

Mathematics
2 answers:
Marysya12 [62]3 years ago
8 0
A-false
B-true
C-true
D - true
zheka24 [161]3 years ago
4 0
A = false
b = true
c = true
d = true
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If logx27 + logy4 =5<br>and logx27 - logy4 =1<br>find x and y​
Elanso [62]

Answer:

Hello,

I have reply too quick in comments (sorry)

Step-by-step explanation:

\left\{\begin{array}{ccc}log_x (27)+log_y (4)=5\\log_x (27)-log_y (4)=1\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}2*log_x (27)=6\\2*log_y (4)=4\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}log_x (27)=3\\log_y (4)=2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x^{log_x (27)}=x^3\\y^{log_y (4)}=y^2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}27=x^3\\4=y^2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x=3\\y=2\\\end{array}\right.\\\\

5 0
3 years ago
What is the slope of the line that passes through the pair of points (1/3, -1) and ( -2, 9/2)​
UkoKoshka [18]

Answer:

\boxed{m = - \frac{33}{14} }

.

Step-by-step explanation:

Use the form below

\boxed{\boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }}

Where

  • m is a slope
  • (x_1,~y_1) and (x_2,~y_2) are the point of the line

.

So, the slope is

(\frac{1}{3} ,~ -1) \to x_1 = \frac{1}{3} ~and~y_1 = -1

(-2,~ \frac{9}{2} ) \to x_2 = -2~and~y_2 = \frac{9}{2}

.

m = \frac{\frac{9}{2} -(-1)}{-2-\frac{1}{3} }

m = \frac{\frac{11}{2} }{\frac{-7}{3} }

m = \frac{11}{2} \div (-\frac{7}{3} )

m = \frac{11}{2} \times (-\frac{3}{7} )

m = - \frac{33}{14}

.

Happy to help:)

7 0
3 years ago
Read 2 more answers
A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken
kotegsom [21]

Answer: 68

Step-by-step explanation:

Formula for sample size when prior estimate of population proportion (p) is available:  n=p(1-p)(\dfrac{z^*}{E})^2

, where z*= critical-value.

E= Margin of error.

Let p be the population proportion of  trees are infected with the citrus red mite.

As per given , we have

p=\dfrac{1}{5}=0.2

E= ± 0.08

The critical z-value corresponding to 90% confidence level = z*=1.645

Substitute all the values in the above formula , we get

Required sample size  :n=(0.2)(1-0.2)(\dfrac{(1.645)}{0.08})^2

\Rightarrow\ n=(0.2)(0.8)(20.5625)^2

\Rightarrow\ n=0.16(422.81640625)\\\\\Rightarrow\ n=67.650625\approx68 [Rounded to next integer.]

Thus, the minimum sample size should be taken =68

6 0
3 years ago
Show work please.<br><br> solve system of equations using matrices.
nadya68 [22]

Answer:

(t, t -1, t)

Step-by-step explanation:

You have three unknowns but only 2 equations, so you can't really SOLVE this...you can get a solution with a variable still in it (I forget what this is called.  I think it refers to infinite many solutions).  Here's how it works:

Set up your matrix:

\left[\begin{array}{ccc}1&-2&1\\2&-1&-1\\\end{array}\right] \left[\begin{array}{ccc}2\\1\\\end{array}\right]

You want to change the number in position 21 (the 2 in the scond row) to a 0 so you have y and z left.  Do this by multiplying the top row by -2 then adding it to the second row to get that 2 to become a 0.  Multiplying in a -2 to the top row gives you:

\left[\begin{array}{ccc}-2&4&-2\\2&-1&-1\\\end{array}\right]\left[\begin{array}{ccc}-4\\1\\\end{array}\right]

Then add, keeping the first row the same and changing the second to reflect the addition:

\left[\begin{array}{ccc}-2&4&-2\\0&3&-3\\\end{array}\right] \left[\begin{array}{ccc}-4\\-3\\\end{array}\right]

The second equation is this now:

3y - 3z = -3.  Solving for y gives you y = z - 1.  Let's let z = t (some random real number that will make the system true.  Any number will work.  I'll show you at the end.  Just bear with me...)

lf z = t, and if y = z - 1, then y = t - 1.  So far we have that y = t - 1 and z = t.  Now we solve for x:

From the first equation in the original system,

x - 2y + z = 2.  Subbing in t - 1 for y and t for z:

x - 2(t - 1) + t = 2.  Simplify to get

x - 2t + 2 + t = 2  and  x - t = 0, and x = t.  So the solution set is (t, t - 1, t).  Picking a random value for t of, let's say 2, sub that in and make sure it works.  If:

x - 2y + z = 2, then t - 2(t - 1) + t = 2 becomes t - 2t + 2 + t = 2, and with t = 2, 2 - 2(2) + 2 + 2 = 2.    Check it:  2 - 4 + 4 = 2 and 2 = 2.  You could pick any value for t and it will work.

6 0
3 years ago
Which relation is a function?
Veseljchak [2.6K]

Answer: B


Step-by-step explanation:

because in A it says 2=3 and 2=2 that is not a function each number has to have an outcome of one possible answer if that is true it is a function.

7 0
3 years ago
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