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2 years ago

Solve the equation + 6 = 2.

Mathematics

1 answer:

seraphim [82]2 years ago

6 0

The answer is a=7 because you have to do 7-6 which equals to 2 which a=7 is the right answer

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Please help 20 points

loris [4]

Answer:

10 4/7

Step-by-step i used photo math

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2 years ago

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HELP. WILLGIVE BRAINLIEST Add. 17.4 + 17.7

VashaNatasha [74]

Answer: the answer is 35.1

Step-by-step explanation:

7 0

2 years ago

If logx √2 = 1/6 , then x =?

Kaylis [27]

Step-by-step explanation:

logx√2=1/6

<=> logx(2^1/2)=1/6

<=>1/2.logx(2)=1/6

<=>logx(2)=1/3

<=>2=x^1/3

<=>x=

Sorry I forgot the formula in the last step

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3 years ago

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Quadrilateral ABCD is located at A (−2, 2), B (−2, 4), C (2, 4), and D (2, 2). The quadrilateral is then transformed using the r

Mademuasel [1]

New cordinates are formed by adding 7 in x and subtracting 2 from y
A(−2, 2) =A ' (-2 +7 , 2 - 1 ) = A' (5,1)
B(−2, 4) = B' (-2 + 7 , 4 -1 )= B' (5,3)
C(2, 4) = C' (2 + 7 , 4 -1 )= C' (9,3)
D(2, 2) D' (2 + 7 , 2 -1 ) = D' ( 9 , 1)

8 0

2 years ago

Money Flow The rate of a continuous money flow starts at $1000 and increases exponentially at 5% per year for 4 years. Find the

77julia77 [94]

Answer:

Present value = $4,122.4

Accumulated amount = $4,742

Step-by-step explanation:

Data provided in the question:

Amount at the Start of money flow = $1,000

Increase in amount is exponentially at the rate of 5% per year

Time = 4 years

Interest rate = 3.5% compounded continuously

Now,

Accumulated Value of the money flow = $1000e^{0.05t}$

The present value of the money flow = $\int\limits^4_0 {1000e^{0.05t}(e^{-0.035t})} \, dt$

= $1000\int\limits^4_0 {e^{0.015t}} \, dt$

= $1000\left [\frac{e^{0.015t}}{0.015} \right ]_0^4$

= $1000\times\left [\frac{e^{0.015(4)}}{0.015} -\frac{e^{0.015(0)}}{0.015} \right]$

= 1000 × [70.7891 - 66.6667]

= $4,122.4

Accumulated interest = $e^{rt}\int\limits^4_0 {1000e^{0.05t}(e^{-0.035t}} \, dt$

= $e^{0.035\times4}\times4,122.4$

= $4,742

8 0

2 years ago