Answer:
elipses
Explanation:
According to my research on information technology, I can say that based on the information provided within the question the windows standard in this situation would be to place an ellipses at the end of the caption. This is because in the English language an ellipses (...) usually indicates an intentional omission of a word or sentence, which in computer science is used to give the user an indication that it requires further user input.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
Well when you think about it they both do the same thing but they are diffirent, they have the same perpose but diffirent parts in them so, when you compair them the phone is smaller and slower, the bigger the computer the better it is depending on the amount of money spent on parts.
Answer: The following code is in c++
#include <iostream>
#include<math.h>
using namespace std;
int main()
{
float a,b,c;
cout<<"Enter height and base of triangle\n";
cin>>a>>b; //reading two sides from user
c=sqrt(pow(a,2)+pow(b,2)); //calculating hypotenuse
cout<<"Length of hypotenuse is "<<c; //printing third side of triangle
return 0;
}
OUTPUT :
Enter height and base of triangle
3
4
Length of hypotenuse is 5
Explanation:
In the above code, three variables a, b and c of int type are declared. After that, it is asked from user to enter the value of a and b. The user puts the value and then c is calculated with the help of Pythagoras theorem formulae which squares the values of two sides and then adds them to calculate hypotenuse of a right angled triangle and finally c is printed to console.
Answer:
The solution code is written in Python 3:
- def modifyList(listNumber):
- posCount = 0
- negCount = 0
-
- for x in listNumber:
- if x > 0:
- posCount += 1
- else:
- negCount += 1
-
- if(posCount == len(listNumber)):
- listNumber.append(max(listNumber))
-
- if(negCount == len(listNumber)):
- listNumber.append(min(listNumber))
-
- print(listNumber)
-
- modifyList([-1,-99,-81])
- modifyList([1,99,8])
- modifyList([-1,99,-81])
Explanation:
The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).
To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).
If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).
If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.
At last we can print the listNumber (Line 17).
If we test our function using the three sets of input list, we shall get the following results:
[-1, -99, -81, -99]
[1, 99, 8, 99]
[-1, 99, -81]
Answer:
b.used is 2, b.data[0] is 4, b.data[1] is 6
Explanation:
bag b;
b.insert(5); // b has 5
b.insert(4); // b has 5,4
b.insert(6); // b has 5,4,6
b.erase_one(5); // now 5 is removed , b has 4,6
so no:of elements b.used is 2
b[0]=4;
b[1]=6;
