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PSYCHO15rus [73]
3 years ago
12

Find the indefinite integral ∫((x^2)/(4x^3+9)) dx

Mathematics
1 answer:
Leya [2.2K]3 years ago
6 0

Answer:

\displaystyle  \frac{1}{12}   \ln( |{4x}^{ 3}  + 9|)  +  \rm C

Step-by-step explanation:

we would like to integrate the following indefinite integral:

\displaystyle \int  \frac{ {x}^{2} }{4 {x}^{3}  + 9} dx

in order to integrate it we can consider using u-substitution also known as the reverse chain rule and integration by substitution as well

we know that we can use u-substitution if the integral is in the following form

\displaystyle \int f(g(x))g'(x)dx

since our Integral is very close to the form we can use it

let our u and du be 4x³+9 and 12x²dx so that we can transform the Integral

as we don't have 12x² we need a little bit rearrangement

multiply both Integral and integrand by 1/12 and 12:

\displaystyle  \frac{1}{12} \int  \frac{ 12{x}^{2} }{4 {x}^{3}  + 9} dx

apply substitution:

\displaystyle  \frac{1}{12} \int  \frac{ 1}{u} du

recall Integration rule:

\displaystyle  \frac{1}{12}   \ln(|u|)

back-substitute:

\displaystyle  \frac{1}{12}   \ln( |{4x}^{ 3}  + 9|)

finally we of course have to add constant of integration:

\displaystyle  \frac{1}{12}   \ln( |{4x}^{ 3}  + 9|)  +  \rm C

and we are done!

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