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IrinaVladis [17]
2 years ago
7

What Is a Siamese Fighting Fish and it's average lifespan in captivity?

Biology
1 answer:
nordsb [41]2 years ago
5 0

Answer:

The siamese fighting fish (also commonly known as betta fish) is a freshwater fish found in some parts of asia. They are known to fight other fish of their kind, hence the name siamese <u>fighting</u> fish. They usually live between 2-5 years in captivity.

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Which group of reactions is responsible for the synthesis in photosynthesis?
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Calvin cycle is responsible.
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2 years ago
What is attached to rough ER
KengaRu [80]

Answer:

Rough Endoplasmic Reticulum

Explanation:

Analogy: The golgi apparatus is like the host or hostess because they "deliver" or seat the customers at a table. Function: This organelle acts as a storage unit, water or food, for the cell. Function: This organelle makes proteins to be EXPORTED.

5 0
3 years ago
Due to hunting, the population of Northern elephant seals was reduced to 20 individuals at the end of the 19th century. Since th
anygoal [31]

Answer:

Option C

Explanation:

Long term hunting has led to following  

a) Reduction in population size and hence the gene pool

b) Causation of Bottleneck effect

Due to above factors, the remaining population of Northern elephant seals does not represent the original genetic problem.  

Due to this restriction in mating and genetic variation shall prevail pertaining to reduced gene pool.  

Due to continuous hunting, the gene pool will further shrink, leading to genetic similarity among the organism

Option C is correct

8 0
3 years ago
Which phrase defines a law? a possible explanation or answer to a scientific question that is based on prior knowledge or resear
murzikaleks [220]
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7 0
3 years ago
Read 2 more answers
In a population of rabbits, there are 496 black rabbits and 27 white rabbits. Fur color is determined by a pair of alleles where
Troyanec [42]

Answer:

0.96

Explanation:

It is given that

B is the dominant allele which represents the black color

and b is the recessive allele which represents the white fur.

B being dominant will result into black color fur for genotype "Bb"

Given -

Frequency of black fur allele (p) is 0.8

As per Hardy Weinberg's  first law of equilibrium

p + q = 1\\

Substituting the value of p in above equation, we get -

q = 1-p\\q = 1-0.8\\q= 0.2

q represents the frequency for white fur allele

Frequency of white fur phenotype is

q^2\\= 0.2^2\\= 0.04

Frequency of homozygous black fur phenotype (BB) is

p^2\\= 0.8^2\\= 0.64

As per Hardy Weinberg's second law of equilibrium -

p^2 + q^2 + 2pq = 1\\0.64 + 0.04 + 2pq = 1\\2pq = 1 - 0.68\\2pq = 0.32\\

Combined frequency of homozygous and heterozygous black fur phenotype is

0.64 + 0.32\\= 0.96

5 0
2 years ago
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