This hexagon is split into two congruent trapezoids. You can find the area of one trapezoid and then double it to get the area of the entire hexagon. The formula for area of a hexagon is A = a + b / 2(h), where a and b are the base lengths and h is the height. The given values are as follows:
a = 40
b = 60
h = 24
Let's plug them in and solve.
A = a + b / 2(h)
A = 40 + 60 / 2(24
A = 100 / 2(24)
A = 50(24)
A = 1200
Remember we have to double the area of the trapezoid to get the area of the whole hexagon.
1200 × 2 = 2400
Answer:
The area of the hexagon is 2,400 in².
I think the second one. as a pilgrimage, with some “warring on the side”.
#1 is A & B (points connect)
#2 is A & B & D (because they all touch)
#3 is Plane DFG & Plane GFA
#4 is A & B & D & F
Answer:
m∠SWX=39°, and m∠VWY=51°
Step-by-step explanation:
∠XWU and ∠VWY are vertical angles. Vertical angles are congruent.
∠XWU=∠VWY
we are given ∠XWU=(7x+2)° and ∠VWY=(4x+23)°, so:
7x+2=4x+23
3x+2=23
3x=21
x=7
Now substitute x for 7 in both expressions to get the measures of the angles.
∠XWU=(7(7)+2)°=(49+2)°=51°
∠VWY is also 51° because it is congruent to ∠XWU, but just to make sure:
∠VWY=(4(7)+23)°=(28+23)°=51°
we also need ∠SWX. We can see it makes a right angle with ∠XWU, so their sum is 90°.
∠SWX+51=90
∠SWX=39°
