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3 years ago

How was the first pilgrimage presented?

Mathematics

1 answer:

sdas [7]3 years ago

5 0

I think the second one. as a pilgrimage, with some “warring on the side”.

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What is the mean for the data set?

PIT_PIT [208]

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Just add up all the numbers and divide by 6, as there are six numbers in this set of numbers

7 0

3 years ago

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Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b

poizon [28]

The roots of the given polynomials exist $x=8+\sqrt{10}$ , and $x=8-\sqrt{10}$ .

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\$

$$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\$

$$&x=8+\sqrt{10}, x=8-\sqrt{10}$

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$ , and

$x=8-\sqrt{10}$ .

To learn more about quadratic equations refer to:

brainly.com/question/1214333

#SPJ4

3 0

1 year ago

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PLEASE HELP NOW<br> Solve the equation, then choose the correct answer: <br> -4(8 + 3y ) = 112

wolverine [178]

Answer:

y = -12

Step-by-step explanation:

-4 (8+3y) = 112

-32 -12y = 112

-12y = 144

y = -12

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3 years ago

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Need Help fast, with steps

Hitman42 [59]

Answer:The solution is in the attached file below

Step-by-step explanation:

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3 years ago

What is the slope indicated in the table below?<br> (X) 1 2 3 (y) 5 10 15

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Answer:

Step-by-step explanation:

i d k

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3 years ago