The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
<h3>How to determine the slope?</h3>
The interval is given as:
x = 2 to x = 5
The slope is calculated as:

<u>16. y = 3x - 4</u>
Substitute 2 and 5 for x
y = 3*2 - 4 = 2
y = 3*5 - 4 = 11
So, we have:


Divide
m = 3
Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3
<u>17. y = 2x^2-4x - 2</u>
Substitute 2 and 5 for x
y = 2 * 2^2 - 4 * 2 - 2 = -2
y = 2 * 5^2 - 4 * 5 - 2 = 28
So, we have:


Divide
m = 10
Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
Read more about slopes at:
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Answer:
1. 60%
2. 70
3. 8%
Step-by-step explanation:
I attached pictures to show my work (sorry if they’re a bit messy)!
470 = 8.75(46 - c) + 11c
470 = 402.5 - 8.75c + 11c
67.5 = 2.25c
30 = c
If c = 30 and Soren worked 30 hours in the office, earning $11 per hour, he earns $330 from his office job. 46 - 30 = 16, which should be the remaining amount of hours Soren worked. 16 * 8.75 = 140. He earned $140 from his cashier job. $330 + $140 = $470.
The correct formula to solve this problem is A. 11c + 8.75(46 - c) = 470