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3 years ago

Find the area of the trapezoid.

Mathematics

2 answers:

riadik2000 [5.3K]3 years ago

5 0

Answer:

Step-by-step explanation:

(Top bottom plus bottom bottom )× height divided by 2

(4+6)*6÷2=36

miv72 [106K]3 years ago

5 0

Answer:

36 m²

Step-by-step explanation:

Area of trapezoid is given by,

= 1/2 × sum of the parallel sides × height

$= \frac{1}{2} (8 + 4) \times 6$

$= \frac{1}{2} \times 12 \times 6$

$= 6 \times 6 = 36 {m}^{2}$

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HEY GUYS I NEED THIS ANSWER NOW

Sergio [31]

Let

x-------> the number of fiction books

y-------> the number of nonfiction books.

we know that

$x+y=26$ -----> equation $1$

$x=y+12$

$x-y=12$ -----> equation $2$

Add equation $1$ and equation $2$

$x+y=26\\x-y=12\\ ------\\ 2x=38\\ x=38/2\\x=19\ fiction\ books$

<u>find the value of y</u>

$x+y=26$

$19+y=26$

$y=26-19=7\ nonfiction\ books$

therefore

<u>the answer is</u>

Part a) the number of fiction books is $19\ fiction\ books$

Part b) the number of nonfiction books is $7\ nonfiction\ books$

6 0

3 years ago

Read 2 more answers

Please Find the surface area of the sphere. Round your answer to the nearest hundredth.

Lorico [155]

The first thing I did was to be a part of the world and the other is a great way to get the best out of the way and I have to say that I am not a fan of the most important things to do in the future and the other is a great way to get the best out of the way and I have to say that I am

7 0

3 years ago

In a lab experiment, a student is trying to apply the conservation of momentum. Two identical balls, each with a mass of 1.0 kg.

muminat

Answer:

Trial- 2 shows the conservation of momentum in a closed system.

Step-by-step explanation:

Given: Mass of balls are $m= 1.0\ kg$

Conservation of momentum in a closed system occurs when momentum before collision is equal to momentum after collision.

Let initial velocity of ball $A\ is\ u_1$
Initial velocity of ball $B\ is\ u_2$
Final velocity of ball $A\ is\ v_1$
Final velocity of ball $B\ is\ v_2$
Momentum before collision $= mu_1+mu_2$
Momentum after collision $=mv_1+mv_2$

Now, According to conservation of momentum.

Momentum before collision = Momentum after collision

$mu_1+mu_2=mv_1+mv_2$

We will plug each trial to this equation.

Trial 1

$mu_1+mu_2=mv_1+mv_2\\1.0(1)+1.0(-2)=1.0(-2)+1.0(-1)\\1-2=-2-1\\-1=-3$

Trial 2

$mu_1+mu_2=mv_1+mv_2\\1.0(.5)+1.0(-1.5)=1.0(-.5)+1.0(-\.5)\\.5-1.5=-.5-.5\\-1=-1$

Trial 3

$mu_1+mu_2=mv_1+mv_2\\1.0(2)+1.0(1)=1.0(1)+1.0(-2)\\2+1=1-2\\3=-1$

Trial 4

$mu_1+mu_2=mv_1+mv_2\\1.0(.5)+1.0(-1)=1.0(1.5)+1.0(-1.5)\\.5-1=1.5-1.5\\-.5=0$

We can see only Trial 2 satisfies the princple of conservation of momentum. That is momentum before collison should equal to momentum after collision.

5 0

3 years ago

Here is a situation: I have $5. I save $2 each week. How many weeks do I need to save until i have atleast $50? write the inequa

skad [1K]

Answer:

50 % 2 = 25 25 is the answer

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Efren leaves home at 9am and walks 4 miles per hour. His brother, gregory leaves half an hour later and runs 8.5 miles per hour

Sholpan [36]

Answer:

Gregory will catch up Efren after 26 minutes 40 seconds.

Explanation:

Distance traveled = Speed x Time

Speed of Efren = 4 mi/h

Speed of Gregory = 8.5 mi/h

Let the time of catch up be t hours.

Time of journey of Efren before catch up = (t+0.5)hours, since he starts before half hour.

Distance traveled by Efren = 4 x (t+0.5) miles

Time of journey of Gregory before catch up = t hours.

Distance traveled by Gregory = 8.5 x t miles

If they catch up the distance traveled by them is same, so equating both distances.

4 x (t+0.5) = 8.5 x t

4.5t = 2

t = 0.44 hours =26.67 minutes = 26 minutes 40 seconds.

So Gregory will catch up Efren after 26 minutes 40 seconds.

5 0

3 years ago