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Bad White [126]

3 years ago

5

The mean cost of a five pound bag of shrimp is 46 dollars with a standard deviation of 7 dollars. If a sample of 49 bags of shri

mp is randomly selected, what is the probability that the sample mean would differ from the true mean by more than 0.5 dollars

1 answer:

muminat3 years ago

4 0

Answer:

Step-by-step explanation:

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Solve the simultaneous equations<br> y = 9 - X<br> y = 2x2 + 4x + 6

kenny6666 [7]

Answer:

$\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}$

$\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}$

Step-by-step explanation:

Given the simultaneous equations

$y=9-x$

$y\:=\:2x^2\:+\:4x\:+\:6$

Subtract the equations

$y=9-x$

$-$

$\underline{y=2x^2+4x+6}$

$y-y=9-x-\left(2x^2+4x+6\right)$

$\mathrm{Refine}$

$x\left(2x+5\right)=3$

$\mathrm{Solve\:}\:x\left(2x+5\right)=3$

$2x^2+5x=3$ ∵ $\mathrm{Expand\:}x\left(2x+5\right):\quad 2x^2+5x$

$\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}$

$2x^2+5x-3=3-3$

$\mathrm{Solve\:with\:the\:quadratic\:formula}$

$\mathrm{Quadratic\:Equation\:Formula:}$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=5,\:c=-3:\quad x_{1,\:2}=\frac{-5\pm \sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}v\\$

$x=\frac{-5+\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$=\frac{-5+\sqrt{5^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$=\frac{-5+\sqrt{49}}{2\cdot \:2}$

$=\frac{-5+\sqrt{49}}{4}$

$=\frac{-5+7}{4}$

$=\frac{2}{4}$

$=\frac{1}{2}$

Similarly,

$x=\frac{-5-\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}:\quad -3$

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=\frac{1}{2},\:x=-3$

$\mathrm{Plug\:the\:solutions\:}x=\frac{1}{2},\:x=-3\mathrm{\:into\:}y=9-x$

$\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}\frac{1}{2}:\quad y=\frac{17}{2}$

$\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}-3:\quad y=12$

$\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}$

$\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}$

3 0

3 years ago

Find the value of 7 Y if 3 bracket Y - 1 bracket is equal 21

lawyer [7]

Answer:

$7y = 56$

Step-by-step explanation:

$3(y - 1) = 21$

Divide 3 on both sides:

$y - 1 = 7$

Add 1 to both sides:

$y = 8$

Multiply by 7 on both sides:

$7y = 56$

8 0

3 years ago

It takes 34 pounds of seed to completely plants 5 acre field. How many pounds of seed are needed per acre?

Nataly [62]

Answer:

Step-by-step explanation:

Since 34 Lbs of seed is needed for 5 Acre's, You will need two find 1/5th of 34.

1/5 in decimal form is 0.2

34*0.2= 6.8

In order to cover 1 Acre of land you will need 6.8 lbs of seed.

Hope this helps!

6 0

3 years ago

I need help SHOW YOUR WORK

earnstyle [38]

Answer:

$F)\displaystyle \: 100\pi{ x}^{8} {y}^{2} {z}^{ 6}$

Step-by-step explanation:

we are given r and the formula

we want to find the surface area of the shpare with the given r

to do so

we need our algebra skills

substitute the value of r:

$\displaystyle \: S = 4\pi( {5x}^{4} y {z}^{ 3} {)}^{2}$

recall law of exponent

$\displaystyle \: ({x}^{m} {)}^{n} \iff \: {x}^{mn}$

to simplify:

$\displaystyle \: S = 4\pi({ {5}^{2} x}^{4 \times 2} {y}^{1 \times 2} {z}^{ 3 \times 2} )$

simplify multiplication:

$\displaystyle \: S = 4\pi({ 25x}^{8} {y}^{2} {z}^{ 6} )$

distribute:

$\displaystyle \: S = 100\pi{ x}^{8} {y}^{2} {z}^{ 6}$

hence our answer is F

5 0

3 years ago

1. Simplify the expression:<br> 4+36+(10-8)’-3+7<br> A. 130<br> B. 100<br> C. 38<br> D. 37

Alika [10]

Answer:

The answer isn't in the options anyway I'll write it. the answer is 46.

Step-by-step explanation:

According to BODMAS rule - addition should be done first so

4+36= 40 and -3 +7 = 4 so 40+4 ,= 44

then we should do subtracting so, 10-8 = 2

to conclude we should bring the equation to an end so,

44+2 = 46

HOPE THIS HELPS YOU

6 0

3 years ago