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3 years ago

Please answer this correctly

Mathematics

1 answer:

MAVERICK [17]3 years ago

7 0

Answer:

1:50 PM

Step-by-step explanation:

Left school at 10:38 AM,

took them 51 minutes,

38+51=89,

89-60=29,

so when they drove to the museum, it was 11:29 AM.

From here, they stayed at the museum for 1 hour and 26 minutes,

so they stayed at the museum until 12:55 AM since 29+26=55.

Now, it took them 55 minutes to drive back to the school,

so 12:55 plus another 55 minutes,

it's going to be 1:50 PM when Dale's class got back to school.

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Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k

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Answer:

$\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k, the vector projection of B unto a is expressed as $proj_ab = \dfrac{b.a}{||a||^2} * a$

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||² = 130

$proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\$

Hence the projection of b unto a is expressed as $\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

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3 years ago

Kate begins solving the equation (6x – 3) = (6x – 4). Her work is correct and is shown below. (6x – 3) = (6x – 4) 4x – 2 = 3x –

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Answer:

x = 0.

Step-by-step explanation:

4x = 3x

4x - 3x = 0

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Step-by-step explanation:

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In an input/output table, all outputs are 0, regardless of the input. What could the function equation be? Select all that apply

marysya [2.9K]

Answers:

choice A) y = 0x

choice D) y = 0/x

========================================================

Explanation:

Choice A is the same as y = 0 because 0x turns into 0. Multiplying 0 with any number always leads to 0.

Similarly, choice D is the same as y = 0 as well. Dividing 0 over any nonzero value leads to 0. Note the key term "nonzero" here. We cannot have 0 in the denominator. So x = 0 is not allowed for choice D.

So for any nonzero x, we have 0x and 0/x result in the same thing.

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Extra info:

Choice B can be ruled out because something like x = 2 leads to y = 2.

Choice C is ruled out because we can never have 0 in the denominator.

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