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Delicious77 [7]

3 years ago

6

Can someone help me out?

1 answer:

Lapatulllka [165]3 years ago

8 0

502.7 is the answer!

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The hypotenuse of a 45 45 90 triangle measures 24 inches. what is the length of one leg of the triangle?

frosja888 [35]

Answer:

$12\sqrt{2}\ in$

Step-by-step explanation:

we know that

A $45\°-45\°-90\°$ right triangle has two equal legs

Let

x-----> the length side of the leg of the triangle

y------> the length side of the hypotenuse

$sin(45\°)=cos(45\°)=\frac{\sqrt{2}}{2}$

$cos(45\°)=\frac{x}{y}$

so

$\frac{x}{y}=\frac{\sqrt{2}}{2}$

in this problem we have

$y=24\ in$

substitute the value of y and solve for x

$\frac{x}{24}=\frac{\sqrt{2}}{2}$

$x=24\frac{\sqrt{2}}{2}$

$x=12\sqrt{2}\ in$

5 0

3 years ago

Read 2 more answers

Which is greater 0.75 or 3 over 16

Lana71 [14]

Answer:

.75

Step-by-step explanation:

because if you turn .75 into a fraction it is 1/4

P.S would appreciate brainliest

7 0

3 years ago

PLEASE HELP ME (Above)

blondinia [14]

Answer:

the answer is 50% hehe :)

3 0

3 years ago

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Select the two values of x that are roots of this equation.<br> 2x+11x+15= 0

Amiraneli [1.4K]

Answer:

The roots of the equation are x=-3 and x=-2.5

Step-by-step explanation:

<u><em>The correct quadratic equation is</em></u>

2x^2+11x+15=0

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^{2} +11x+15=0$

so

$a=2\\b=11\\c=15$

substitute in the formula

$x=\frac{-11(+/-)\sqrt{11^{2}-4(2)(15)}} {2(2)}$

$x=\frac{-11(+/-)\sqrt{121-120}} {4}$

$x=\frac{-11(+/-)\sqrt{1}} {4}$

$x=\frac{-11(+/-)1} {4}$

$x_1=\frac{-11(+)1}{4}=-2.5$

$x_2=\frac{-11(-)1}{4}=-3$

therefore

The roots of the equation are x=-3 and x=-2.5

5 0

3 years ago

Given |u| = 2.5, |v| = 3.2, and the angle between the vectors is 60°, find the value of u · v?

Alenkasestr [34]

Step-by-step explanation:

u.v=|u||v|cos60°

u.v=(2.5)(3.2)(1/2)

u.v=(8)(1/2)

u.v=4

4 0

3 years ago