3x⁶y² + 57x⁵y³ + 252x⁴y⁴
= 3x⁴y²(x² + 19xy + 84y²)
= 3x⁴y²(x² + 12xy + 7xy + 84y²)
= 3x⁴y²(x(x + 12y) + 7y(x + 12y))
= 3x⁴y²(x + 12y)(x + 7y)
Answer:
1 1/2 lbs and 2 1/4 lbs
Step-by-step explanation:
1st rectangle:
width: 2.48cm
length: 4.96
2nd rectangle:
width: 4.96 (equals to the length of the 1st rectangle)
area: 9.92
length: 9.92/4.96 = 2
Let x represent the side length of the square end, and let d represent the dimension that is the sum of length and girth. Then the volume V is given by
V = x²(d -4x)
Volume will be maximized when the derivative of V is zero.
dV/dx = 0 = -12x² +2dx
0 = -2x(6x -d)
This has solutions
x = 0, x = d/6
a) The largest possible volume is
(d/6)²(d -4d/6) = 2(d/6)³
= 2(108 in/6)³ = 11,664 in³
b) The dimensions of the package with largest volume are
d/6 = 18 inches square by
d -4d/6 = d/3 = 36 inches long
Answer: D = 70
A = 30
Explanation: d is parallel to 70 degrees, 40 is parallel to e, and the whole set of angles is 180 so 180 - 2(70) + 2(40) = 30 so D = 70 and A = 30