Pia needs 100 red beads to make a necklace. She already has 38 red beads. How many more beads does she need?

HELP PLZ GUYS I BEG YOU 15 PTS ITS EASYYYYYYY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Aliun [14]

Answer:

1) The linear equation in point and slope form is y - 67 = -4 × (x - 14)

2) The variables are;

a) The number of candies available = y

b) The number of days Jennifer eats the candies =

c) The slope, m = -4

3) Jennifer received 123 pieces of candies on Halloween

Step-by-step explanation:

The given parameters are;

The number of candies Jennifer eats everyday = 4 pieces

The number of days for which Jennifer eats the daily 4 candies = 14

The number of candies left at the end of the 14th day = 67 candies

1) We note that the rate of decrease in the number of candies = 4 candies/day

Therefore, the slope of the linear equation is m = -4

The y-intercept = The initial amount of candies Jennifer has = c = 67 + 14× 4 = 123 candies

The linear equation in point and slope form is given as follows;

y - 67 = -4 × (x - 14)

2) The variables are;

a) The y-value represents the number of candies available on a specific day

b) The x value represents the number of days Jennifer eats the candies'

c) The slope = The rate of decrease in the number of candies per day = -4

3) The number of candies Jennifer receives on Halloween is given by the y-intercept of the straight line equation as follows;

y - 67 = -4 × (x - 14)

y - 67 = -4·x + 56

y = -4·x + 56 + 67 = -4·x + 123

y = -4·x + 123

Comparing the above equation, with the general form of the straight line equation, y = m·x + c, where, the constant term, c = The y-intercept, we have;

The y-intercept of the equation y = -4·x + 123 = 123 = The initial amount of candies Jennifer received on Halloween.

6 0

3 years ago

1. The image below represents the dimensions of

andreyandreev [35.5K]

Answer:

V plus 5 is four

Step-by-step explanation:

dimensions of

Mike's Bike ramp in feet. How far does Mike have to

ride to reach the end of his ramp? Give the exact

distance.

V

5

10

SIMPLIFY THE RADICAL.

Hold on, our servers are swamped. Wait for your answer to fully load. dimensions of

Mike's Bike ramp in feet. How far does Mike have to

ride to reach the end of his ramp? Give the exact

distance.

V

5

10

SIMPLIFY THE RADICAL.

Hold on, our servers are swamped. Wait for your answer to fully load. dimensions of

Mike's Bike ramp in feet. How far does Mike have to

ride to reach the end of his ramp? Give the exact

distance.

V

5

10

SIMPLIFY THE RADICAL.

Hold on, our servers are swamped. Wait for your answer to fully load. dimensions of

Mike's Bike ramp in feet. How far does Mike have to

ride to reach the end of his ramp? Give the exact

distance.

V

5

10

SIMPLIFY THE RADICAL.

Hold on, our servers are swamped. Wait for your answer to fully load. dimensions of

Mike's Bike ramp in feet. How far does Mike have to

ride to reach the end of his ramp? Give the exact

distance.

V

5

10

SIMPLIFY THE RADICAL.

Hold on, our servers are swamped. Wait for your answer to fully load. dimensions of

Mike's Bike ramp in feet. How far does Mike have to

ride to reach the end of his ramp? Give the exact

distance.

V

5

10

SIMPLIFY THE RADICAL.

Hold on, our servers are swamped. Wait for your answer to fully load. dimensions of

Mike's Bike ramp in feet. How far does Mike have to

ride to reach the end of his ramp? Give the exact

distance.

V

5

10

SIMPLIFY THE RADICAL.

Hold on, our servers are swamped. Wait for your answer to fully load. dimensions of

Mike's Bike ramp in feet. How far does Mike have to

ride to reach the end of his ramp? Give the exact

distance.

V

5

10

SIMPLIFY THE RADICAL.

Hold on, our servers are swamped. Wait for your answer to fully load.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=10-%5Cfrac%7B3y-1%7D%7B2%7D%20%3D%5Cfrac%7B6y%2B3%7D%7B11%7D" id="TexFormula1" title="10-\frac

Ghella [55]

$10-\frac{3x-1}{2} =\frac{6x+3}{11}$

$10 = \frac{6x+3}{11} + \frac{3x-1}{2}$

$10 = (\frac{6x+3}{11} \times \frac{2}{2} ) + (\frac{3x-1}{2} \times \frac{11}{11} )$

$10 = ( \frac{2(6x + 3)}{22} ) + ( \frac{11(3x - 1)}{22} )$

$10 = \frac{12x + 6}{22} + \frac{33x - 11}{22}$

$10 = \frac{12x + 6 + 33x - 11}{22}$

$10 = \frac{(12 x + 33x) + (6 - 11)}{22}$

$10 = \frac{45x - 5}{22}$

$10 \times 22 = 45x - 5$

$220 = 45x - 5$

$220 + 5 = 45x$

$225 = 45x$

$\frac{225}{45} = x$

$\frac{45}{9} = x$

$5 = x$

7 0

2 years ago

Brainliest is given to the correct answer.

Svet_ta [14]

Answer:

c

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Becky put $100 into in the account to use for school expenses. The account earns 11% interest, compounded annually. How much wil

Mnenie [13.5K]

Answer: $187 will be in the account after 6 years.

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = $100

r = 11% = 11/100 = 0.11

n = 1 because it was compounded once in a year.

t = 6 years

Therefore,.

A = 100(1 + 0.11/1)^1 × 6

A = 100(1 + 0.11)^6

A = 100(1.11)^6

A = $187

5 0

3 years ago